Physics: Post your doubts here!

[Mohammed salik]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

Yeh Cheez..! Sorry Yaar..! I was About to Start Typing !

 

[Thought blocker]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

Yes did the same way

 

[Mohammed salik]

Jaldi please.

Yeh Cheez..! Sorry Yaar..! I was About to Start Typing !

 

[Thought blocker]

yound modulus=stress/strain
E=Fl/Ae
(2.1x10^11)= (70 x 9.81) x (20) / ((3.2 x 10^6)x(200) x e)
e= 13734 / (( 2.1 x 10^11) x ( 6.4 x 10^-4))
e= 1.02 x 10^-4 m
e= 0.1 mm

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

 

[mehria]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

ur statement is correct
due to same force actng on each charge the electric field strength is also same for both...

 

[Mohammed salik]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

Derivation f Formula E = v / d ? :-

 

[Thought blocker]

ur statement is correct
due to same force actng on each charge the electric field strength is also same for both...

Derivation f Formula E = v / d ? :-

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

 

[mehria]

In question 31, he wants elaboration of formula E = v / d , elaborate it, coz I can only tell that greater the charge the more the electric field. since both Experiences a same force F it should be F/q. or u could say like F=E*charge now since F is constant if u increase the electric field strength u decrease the charge

it is all abt E= F/Q.. not E=V/d

 

[mehria]

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

but E=V/d is for the charges that are present between two oppositely chargd plates.. where as in ths question we r nt told that the charge is placed in between the two oppositely chrgd plates so we will work out our ans by considering E=F/Q

 

[Mohammed salik]

Look For Formula E= V/d ... First thing is You Have to Know Electric Field= F/q
Work Done is = F * d
And We Know Voltage or EMF= Workdone ( w)/ Unit Charge (q)
So We can Say W=Voltage * Charge
Then
F*d=V*q
F/q=V/d
So we can Say E= v/d!!
And You did Give Him correct Explanation ..! Where Exactly His confusion is ?

But that guy needs more elaboration, I know I am correct, but I can't elaborate more then that ._.

 

[Thought blocker]

it is all abt E= F/Q.. not E=V/d

but E=V/d is for the charges that are present between two oppositely chargd plates.. where as in ths question we r nt told that the charge is placed in between the two oppositely chrgd plates so we will work out our ans by considering E=F/Q

I mean to say is it is formula based question yaar :/

 

[Thought blocker]

Look For Formula E= V/d ... First thing is You Have to Know Electric Field= F/q
Work Done is = F * d
And We Know Voltage or EMF= Workdone ( w)/ Unit Charge (q)
So We can Say W=Voltage * Charge
Then
F*d=V*q
F/q=V/d
So we can Say E= v/d!!
And You did Give Him correct Explanation ..! Where Exactly His confusion is ?

Bas I think now it might be clear

 

[MYLORD]

If any1 could help me with these doubts

 

[mehria]

If any1 could help me with these doubts


View attachment 43767 View attachment 43768 View attachment 43769 View attachment 43770 View attachment 43771 View attachment 43772

can u share the link...?

 

[ZaqZainab]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w04_qp_1.pdf
Q18 a little explanation will do
Q20
q25 i get why the answer is C but whats wrong with D

 

[Mohammed salik]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_1.pdf
Q18 a little explanation will do
Q20
q25 i get why the answer is C but whats wrong with D

Q18 )W=F*d= 9*1000 * 40 =360000 J
Gain in GPE= Weight * h = 20*1000*12=240000
Heat Lost = 360000-240000=120000J
Ans is A

 

[Mohammed salik]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_1.pdf
Q18 a little explanation will do
Q20
q25 i get why the answer is C but whats wrong with D

q20 Credits to Him!

chocolate_girl
question number 7
the air resistance is zero. the only acceleration is of gravity. and on earth gravity is a constant which will be same for any points on that trajectory.
question numnber 20
View attachment 39803
View attachment 39804

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_1.pdf
Q18 a little explanation will do
Q20
q25 i get why the answer is C but whats wrong with D

25) D is wrong, coz we are not provided with value of V so you can't get the wavelength.

 

[ZaqZainab]

25) D is wrong, coz we are not provided with value of V so you can't get the wavelength.

V what?

 

[ZaqZainab]

q20 Credits to Him!

thanks