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Physics: Post your doubts here!

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Hi , I need help

9702/11/M/J/14
Q13,31,

9702/12/M/J/14
Q10, 15, 18, 23,30,35

9702/13/M/J/14
Q14, 16,23,35,38

Thank You in advance
 
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Hi , I need help

9702/11/M/J/14
Q13,31.

Thank You in advance
13)
900x0.2=180Nm
the torque by F will be Fx1.2=180
hence F will be 150N
31)
Energy transfer = I²Rt = (40 x 10⁻³)² x 250 x 60 = 24J and During this time 6.0J of energy is lost in the
internal resistance. The battery must therefore supply a total of 30 J of energy to the whole circuit.
Q = It
Q = (40 x 10⁻³)² x 60 =2.4C
and so the e.m.f. of the battery is (30J / 2.4C) = 12.5V.
 
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aoa thank you admin for the help, but the Paper 2 & Paper 4 : http://www.mediafire.com/?g65j51stacmy33c, link is not working please uplode the file again or send me a new link
Hi everyone, AsSalamoAlaikum Wr Wb...

To get things organized in a better way, I am making this thread. As othewise, some queries remain unanswered!

So post your PHYSICS doubts in this thread. InshaAllah other people here will help me and you all. :D ;)

NOTE: If any doubts in the pastpapers, please post the link! You can find links here!

Any Physics related notes and links will be added here in this post. Feel free to provide the links to your notes around the forum, or any other websites! :)
Thanks!
Jazak Allah Khair!


Physics Notes:

Some links & Notes - by destined007

As physics p1 MCQS YEARLY Solved [explaination]
Physics Practical Tips - by arlery

Notes for A2 Direct Sensing (Applications) - shared by sweetiepie

Physics Summarised Notes (Click to download)

AS and A-Level Physics Definitions

A2: Physics Revision notes - by smzimran

Paper:5 Finding uncerainty in log - by XPFMember

Physics Paper 5 tips - by arlery

Physics Compiled Pastpapers: <Credits to CaptainDanger for sharing this..>

Here are the compiled A level topical Physics questions in PDF form...

Paper 1 : http://www.mediafire.com/?tocg6ha6ihkwd

Paper 2 & Paper 4 : http://www.mediafire.com/?g65j51stacmy33c

(Source : http://www.alevelforum.com/viewtopic.php?f=15&t=14)
 
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In this why can't we just use the o.6o as the perpendicular distance between the forces
and where is the pivot :/
 

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Why can't we consider the car and balancing weight as a single object and add their masses and subsitute them in the formula F=ma where F will be the total weight of both?
 

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Why isn't it C? cause minimum force will be when force is applied furthest point from the hinge right ?
 

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