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How do you ask that blogger to solve some questions. I mean where to post the comments?for 33 see solution 387 at
http://physics-ref.blogspot.com/2015/02/physics-9702-doubts-help-page-71.html
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How do you ask that blogger to solve some questions. I mean where to post the comments?for 33 see solution 387 at
http://physics-ref.blogspot.com/2015/02/physics-9702-doubts-help-page-71.html
I searched the blog for june 2003 but only two of these i found solved (35 and 10) rest i couldnt find :/ Any help?Many of these have already been solved. Could you search in the specific paper at
http://physics-ref.blogspot.com/2014/05/physics-9702-notes-worked-solutions-for.html
20. HereCan someone explain these to me? Physicist
View attachment 54164 View attachment 54165 View attachment 54166 View attachment 54167 View attachment 54168
how do we know if the sphere is stationary or moving up/ down ? :/ may be its weight is greater than upthrust,who knows? how can we assume it to be moving upwards & conclude that R is greater than P :/
the answer is A can anyone explain with the calculation
The extension provided by each spring is e.
X: Springs are in parallel so extension will be 1/e+1/e=1/(resultant extension). Hence resultant extension is e/2.
Y: For both the series combinations the extension is 2e. Considering the parallel combinations: 1/2e+1/2e=1/(resultant extension). Hence resultant extension is e.
Z: For parallel springs extension is e/2 and when added to the 3rd spring the total extension is 3e/2.
So order of increasing extension is X-Y-Z.
According to Young Modulus formula: F=EAe/l, force is directly proportional to area and inversely proportional to length.And this one the answer is D
The weight of one person is 588.6 N so weight of 20 people will be 11772 N.Help needed
why is 2 wrong?
The ammeter is reading the current in that line down there flowing through that resistor next to it. The resistor has potential difference V across it equal to that of the emf of the battery since it is a parallel circuit. The resistor also has its own resistance R. Both of these quantities do not change when the variable resistor's resistance increases. Therefore the current remains the same. Had the ammeter been placed in that branch with the variable resistor, the reading would have decreased.ans is C... y does the ammeter reading remain unchanged??
But the fact that the overall resistance in the circuit increases, doesn't that change the current in the circuit?The ammeter is reading the current in that line down there flowing through that resistor next to it. The resistor has potential difference V across it equal to that of the emf of the battery since it is a parallel circuit. The resistor also has its own resistance R. Both of these quantities do not change when the variable resistor's resistance increases. Therefore the current remains the same. Had the ammeter been placed in that branch with the variable resistor, the reading would have decreased.
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