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Physics: Post your doubts here!

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Fom 12:00 to 12:30 distance coveref is 100 miles
From 12:30 to 1:30 distance covered is 200 miles.
Total distance covered = 300 mile so outside of range of cambridge
Remaining distance to covere = 80 mile but we only have fuel for another 50 miles since fuel for 300 miles is used up so emergency langding.
It has traveled 100 miles in the y direction till 12:30.
After that it travels 200sin45 in the y direction and 200cos45 in the x direction.
So total is 100+200sin45 in y direction and 200cos45 in x direction.
Square both and then add. Then take square root to get distance from Cambridge.
 
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Distance XZ is constant.
If speed is high then XZ is covered quickly so t is less.
If speed is low (after rebound inelastic) XZ is covered in more time.

You must also compare area under vt graph. XZ is constant so area must remain constant.
XY isn't constant,no? because the question says it comes to rest somewhere between XY so we don't exactly know if it returns to its initial position?
 
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XY isn't constant,no? because the question says it comes to rest somewhere between XY so we don't exactly know if it returns to its initial position?
Sorry. Read All XZ as YZ. I was talking about the Flat area.

Distance YZ is constant.
If speed is high then YZ is covered quickly so t is less.
If speed is low (after rebound inelastic) YZ is covered in more time.

You must also compare area under vt graph. YZ is constant so area must remain constant.
 
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11356189_941477912539066_1314603987_n.jpg
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how B?
E= stress/strain= F/A/x/l
E=Fl/xA
E=Fl/ delta l (l^2)
E and F are both constant, so B
 
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The net work done should be the area between the unloading and loading line ,no? :unsure:
The area between is the thermal energy dissipated. For a rubber, when it is extended they say that there is no permanent extension, however there will be heat exerted. The shaded area is the net work done and the area under the graph is the work recovered
 
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