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The switch is always connected to the positive terminal of the battery so C and D are ruled outcan someone explain q 36 in paper 11 may june 2017 ...
Thanks bruh!The switch is always connected to the positive terminal of the battery so C and D are ruled out
We need a voltage between 5 and 7V so if we look at A, the output is 1/2 x 9= 4.5V which is not bw the specified range
In B the output is 2/3 x 9= 6V which is within the range so B is the correct option
ohhh..thank you i never knew about the switch thingThe switch is always connected to the positive terminal of the battery so C and D are ruled out
We need a voltage between 5 and 7V so if we look at A, the output is 1/2 x 9= 4.5V which is not bw the specified range
In B the output is 2/3 x 9= 6V which is within the range so B is the correct option
d = 100mView attachment 64137 is there any other method to do this?
I think that it is the lower one wire which is at zero potentialohhh..thank you i never knew about the switch thing
, but what did they mean when they said that a pd of 0v to its input at one switch position
The distance would be 200md = 100m
u = 10m/s
v = 20m/s
v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²
No it's DIs the answer B? View attachment 64138
yes.Is the answer B? View attachment 64138
Wait isint it b??No it's D
t would be 100 as we take inital 10The distance would be 200m
D=200*
For 100no i
t would be 100 as we take inital 10
t passes the marker it's speed is 10 so u=10.For 100
Initial is zero
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