- Messages
- 1,229
- Reaction score
- 740
- Points
- 123
🚀 NEW from the xtremepape.rs team: AI exam prep — 120,000+ worked solutions, and it marks your handwritten working from a photo. Sign in with your forum account & try it free → prepare.xtremepape.rs
i hope you get itwhy can't it be b?
but then shouldn't it be 2/1 instead of 1/2?i hope you get it![]()
When we calculate Escape Speed, we use the formula square root[2GM/R]. Here why do we assume the radius,r, as the radius of Earth,R? Escape speed is the speed with which a body moves from gravitational field to infinity. What if its initial position in the gravitational field from where it escaped to infinity was not on the surface of Earth? Why do we use R? Shouldnt we use r as the distance of its initial position from centre of the Earth?
If a body is present in the Earth's gravitational field, but not on the surface of Earth, then it escapes to infinity. The formula of its escape speed is square root(2GM/r). Here, why r is taken as the radius of Earth?are you referring to a specific question. if yes, tell me which question it is
So Escape speed is only when an object escapes from the surface of Earth and not from any other point in Earth's Gravitational field?take a look again at the derivation of escape speed. i have added as solution 358 at
http://physics-ref.blogspot.com/2015/02/physics-9702-doubts-help-page-59.html
maybe you are misunderstanding things
yeah
Shdnt the elastic limit be exctly at T, bcz if force equivalent to the value of force at T is applied, the wire still regains its original shape and length?2 of them is explained at
http://physics-ref.blogspot.com/2015/02/physics-9702-doubts-help-page-59.html
🚀 NEW from the xtremepape.rs team: AI exam prep — 120,000+ worked solutions, and it marks your handwritten working from a photo. Sign in with your forum account & try it free → prepare.xtremepape.rs