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How do we calculate the time in part (d)(1) and (2)? Help please.
Well firstly. you need to look at all the data you already have.
From (b), you've got the initial acceleration which is 0.570 ms^-2.
You also have the constant velocity which is 2.00 ms^-1.
You have the deceleration too, which you calculated to be 0.306 ms^-2.
You already have the formula written down, but re-arrange it to make t the subject.
t = v-u/a
For 1) t = 2.00 - 0 ( it starts from rest ) / 0.570, this gives you t = 3.5 seconds.
For 2) t = 0-2.00 / (-)0.306 ( since its decelerating ), this gives you t = 6.5 seconds.
Hope that helped! ^_^