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Thanks! But even if Q is moving fastest, it's at equilibrium position, so why won't its displacement be zero?
No it's Ais it B? if not, can someone explain please

The car has to do two things: make the boy accelerate forward with a force of 0.5g, and also provide the contact force upwards needed to counter his weight pulling him down with the force of 1g. The resultant of these two forces (left and up) will be diagonally left-up as shown and will have the magnitude of sqrt(1^2 + 0.5^2) = 1.118gView attachment 54447 View attachment 54448 View attachment 54449
Ans: 9C, 4C 22 C
Doubts; Q4: why is it 1.1mg? shouldn't it be 1 mg.. as the car is accelerating horizontally ONLY so the vertical forces must be balanced to give 0 resultant & hence 0 acc in the vertical plane?
Q9 : I didn't get it at all .. why won't the period increase for R as well?
Q22 I tried all the calculations I could, but I couldn't get 0.07J .. Here is one of those;
1/2 * k * x^2
1/2 * ( 6/0.03)* 0.01^2
ans = 0.01 :/
Somebody help please!?![]()

Thanks A lotThe car has to do two things: make the boy accelerate forward with a force of 0.5g, and also provide the contact force upwards needed to counter his weight pulling him down with the force of 1g. The resultant of these two forces (left and up) will be diagonally left-up as shown and will have the magnitude of sqrt(1^2 + 0.5^2) = 1.118g
As for the pendulum, the only real thing that affects it is the length of the string. The reason why mass is not included is just like why two objects with different masses have the same gravitational acceleration. Although force is proportional to mass, acceleration is inversely proportional. What I'm saying is, the bob has angular acceleration due to gravity, and gravitational acceleration is not affected by mass.
View attachment 54450
Look at this image. It shows the area you should be calculating... The extra strain energy after having extended it by 0.03m already using a 6N load, and then extending it by 0.01 further. It's a trapezium, or difference of area between two triangles.
k = 6/0.03 = 200Thanks A lot
Can you please also explain why can't we use 1/2 K*x2 formula for strain energy here? Or if we can use it , the way I have used it gives me a wrong answer, why.?
Thanks Again !![]()
http://onlineexamhelp.com/wp-content/uploads/2013/11/9702_w12_qp_13.pdf
can someone pls help me with question 33, the answer is D
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