hello? there r mny which one...pacific?...internation as / a level cambridge?/Ahhhhhhhhhhhhhh!!!! That makes sense now! so probability of decay and decay constant are 2 different things
do you have the book? Page 399 it explains it
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Physics: Post your doubts here!
- Thread starter XPFMember
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cambridge international AS and A level by david sang and graham jones
second edition but i think itll be in first too
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The total energy is negative, as radius of orbit decreases, the total energy will decrease (become more negative). The radius of the orbit obviously decreases.
Potential energy is again negative so it'll decrease
Kinetic energy is positive so it'll increase.
That's how I did it.
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I agree :/
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Help needed with Nov09 (41) q8cii
BE per nucleon = BE * nucleon no.
according to law of conservation of energy total left hand side = total right hand side
as Q is the energy released not the energy holding the nucleons in a nucleus it will be subtracted from the equation
(2 × 1.12) + 3x = 28.28 –17.7
x= 2.78 Mev
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http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-134.html
Q688
Part bi
Shouldn't the ans to part 1 be the ans to part 2 and vice versa?
Because if sampling freq is increased, more details can be recorded hence as the mark scheme says ' smaller changes can be recorded'
And if the no of bits are increased, higher freq can be recorded :s
Q688
Part bi
Shouldn't the ans to part 1 be the ans to part 2 and vice versa?
Because if sampling freq is increased, more details can be recorded hence as the mark scheme says ' smaller changes can be recorded'
And if the no of bits are increased, higher freq can be recorded :s
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Thank you so much
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J10/41 Q9 bi why will the gain decrease?
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Oct11/43
Q11c anyone??
Q11c anyone??
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sharpness is how distinct the edges are which we can't tell unless we see an xray image but we can tell that there is a good contrast because there is a large difference between the absorption in the two media. Th regions that absorb more xrays appear darker than the other.
Yep.
Vout is positive, Green lights, which is in the correct orientation.
Its how it is in the book. I am fairly certain we are correct.
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Yeah
My thought process is that when the Vout is +ve( switch is open),because I always flows from a higher potential to a lower potential,therefore I directIon will be from V out to earth, for the red diode to work it should be placed in a forward bias orientation
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Max p.d is 9 as
single capacitor has C=30
the parallel capacitors have C=60
as C=Q/V, C and V are inversely proportional so first Capacitor takes 2/3 of any p.d across AB.
The max pd across 1st capacitor is 6. so 2/3 of the pd across AB is 6
X*2/3=6
X=9
rules applied to capacitor are opposite to the ones in current electricity
voltage in parallel combination divides and current remains the same
and voltage in series is same and current divides
thus ..as max voltage is 6V..it divides equally between the both parallel capacitors..as each capacitor receives 3V the maximum pd across parallel combination is 3V..and across the one in series is 6V
total maximum pd = 6+3=9V between A and B