Physics practical grams or kg?

[DARK DRAGON]

p was equal to the gradient you calculated while q was equal to ur value of y-intercept

and btw ppl, anyone who calculated the y-intercept from the equation of y=mx + c, then its really not possible for ur gradients to be positive since a positive gradient would give a negative y-intercept and the y-intercept obviously wasn't negative since there were no negative values used in the graph

i used the equation cause i didnt start the y axis at 0 and still got a positive intercept

 

[oldfashionedgirl]

i used the equation cause i didnt start the y axis at 0 and still got a positive intercept

sorry but i still don't think that logically possible really....

 

[DARK DRAGON]

sorry but i still don't think that logically possible really....

np whats done is done

 

[robotic94]

used metres and grams!
gradient was 0.0388
y-intercept was 4.98 * 10^-4

i just messed up in the second question, where you had to take the diameters of the cup and the bowl, i just took it once, whereas you had to take it twice or thrice from different sides.
% uncertanity was 2.4 %
the relationship was wrong!

and Alhamdulillah my paper went awesome!
i was so scared because i messed up chemistry alotttt.. i left soo much! anyways i just hope th gt is very very low!

 

[arkif rizan]

im pretty sure gradient is negative

 

[mujtabashahnawaz]

used metres and grams!
gradient was 0.0388
y-intercept was 4.98 * 10^-4

i just messed up in the second question, where you had to take the diameters of the cup and the bowl, i just took it once, whereas you had to take it twice or thrice from different sides.
% uncertanity was 2.4 %
the relationship was wrong!

and Alhamdulillah my paper went awesome!
i was so scared because i messed up chemistry alotttt.. i left soo much! anyways i just hope th gt is very very low!

If your %age was 2.4% then the relationship was true !

 

[shabby]

View attachment 9652

does this make my point clear? if not prove me to be wrong.

Y was (h0-h0)/X... (h0-h) was increasing but it had to be multiplied by 1/X right (which was decreasing)..so the result was that the calculated values for ((h0-h0/X) were also decreasing...proved..positive gradient

 

[Sarmad Furqan]

Dear people negative gradient is wrong... I've confirmed from my senior teacher..

 

[mujtabashahnawaz]

Lets wait for results, leave everything on God and hope for the best! Now leave the topic

 

[xhizors]

p was equal to the gradient you calculated while q was equal to ur value of y-intercept

and btw ppl, anyone who calculated the y-intercept from the equation of y=mx + c, then its really not possible for ur gradients to be positive since a positive gradient would give a negative y-intercept and the y-intercept obviously wasn't negative since there were no negative values used in the graph

lol whats that logic y intercept will always be positive if on x=0 y >0 and starts inc and thats not necessary at a time both can be positive and negative like value starting from negative y and starts decreasing or from positive y starts increasing...

 

[oldfashionedgirl]

np whats done is done

lol, agreed

 

[oldfashionedgirl]

lol whats that logic y intercept will always be positive if on x=0 y >0 and starts inc and thats not necessary at a time both can be positive and negative like value starting from negative y and starts decreasing or from positive y starts increasing...

a positive gradient means that after substituting it and multiplying it with x in the equation, u'll obv get a positive answer. But after u shift this value to the other side with the value of y, this will become negative.....which means ur answer after subtracting it from y will be negative most prolly, but the y-intercept can't be negative

lets just leave this gradient issue already.....it can't be helped now

 

[xhizors]

 

[Storm Chaser]

I got my gradient positive. and so did 4 of my frnds