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6th march!!! the grade boundary releases on the 5th i guess!!!when is the result ?
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6th march!!! the grade boundary releases on the 5th i guess!!!when is the result ?
1 day after moi bday thats how i rememberwhen is the result ?
march 15...
??6th march!!! the grade boundary releases on the 5th i guess!!!
so soon? sure???6th march!!! the grade boundary releases on the 5th i guess!!!
you are LUCKY1 day after moi bday thats how i remember
lol i aint no lucky it means that i gotta spend my bday thinkin abt my result.. not what actually is supposed to be done on bdaysyou are LUCKY
lol not again.. here to.. ?what??? its written in my statement of entry that the date is 6th march??? Weird!! :O
what trickery is this!!! I don't want to live on this planet anymore!!!lol not again.. here to.. ?
me too!!...what trickery is this!!! I don't want to live on this planet anymore!!!
i guess it was the limit of proportionality. coz i think the second point bfor ultimate tensile strength is spouse to b elastic limit. lol i guess almost evry bdy mixed up stuff there .Okay,i'm worried on this question? in the materials one,what was the labelling of X? limit of proportionality? or elastic limit?
wht did u get for deceleration?burj khalifa question I dd it right ....it was F=ma for part B you do 73-60 then times by 9.81 ...n blah
that question was easy but it took longgg
wht was the last one??? lol i cant remebr just explain it bit so i cld hav clue?omg i was about to do that n i felt its not right! :/ wat about the last mcq? the one with the ball?
it was 0- the value of inital velocity( i forgot divide) by 5,3 the time .....umm i can't rmbrwht
wht did u get for deceleration?
it was that cylinder with metal ball being dropped inw
wht was the last one??? lol i cant remebr just explain it bit so i cld hav clue?
yeah i did it similarly. as long as my memory serves i guess the final answer was sum thin 1.8 or 1.9it was 0- the value i forgot divide by 5,3 the time .....umm i can't rmbr
it was negative somethingwas
yeah i did it similarly. as long as my memory serves i guess the final answer was sum thin 1.8 or 1.9
it was that cylinder with metal ball being dropped in[/qu
oh yes!!! i ticked the option saying ''smaller size ad greater in mass'' coz greater mass il obviously coz the downward force to increase so it will travel in lesser time plus the smaller in size means lesser surface area ad bcoz of this less drag force wil act. therefore the magnitude of total unbalanced force downward il b greaterit was that cylinder with metal ball being dropped in
yup has to b negativ as its a decceleration (negative acceleration)it was negative something
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