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Post all of ur doubts here Mishi :)

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Q1 b part
solve it the way we used to find the error by using fractional error calculations....
first find the density i.e. density=mass/volume
here mass is given n Vol is l^3 so density=580/(6)^3
density= 2.68 g/cm^3

NOW => %uncertainity in density=%uncertainity in mass + %uncertainity in Volume
(d/D) x 100 = ((m/M) + 3(l/L)) x 100
100d/2.68 = ((10/580) + 3(0.1/6)) x 100
100d/2.68 = 6.72
100d = 6.72 x 2.68 => d= 18.00/100 => d=0.18 g/cm^3 <------ ths is the uncertainity in density
always write the value n its uncertainity with the same no. of sig.fg
here 2 s.f. is used as the lowest value given to us is of 2s.f. i.e. 10 n 0.1
so write the density n it's uncertainity to 2 s.f. otherwise u'll lose 1 mark....
 
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Acha part b me post kardungi or wo sab se pehle walde question me akhri part ki mujy samaj nhi aye
 
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Hadia is que me mujy bi samaj nhi aya k A pe current q zero hai or ciii part samaj nhi aya :-/
 

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