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**post your**doubts and i'll try and clear them

- Thread starter applepie1996
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ok i'll check it out now and tell u in a jiffys09 qs 1 need help in calculation of the uncertainty?

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d=m/vs09 qs 1 need help in calculation of the uncertainty?

d=m/length^3

d=580/6.0^3

d=2.69 g cm^-3

for uncertainty:

d=m/length^3

δ d/d = δ m/m + 3 δ l/l

= 10/580 + 3 × 0.1/6.0

= 0.0172 + 0.05

δ d/d = 0.0672

δ d = 0.0672 × 2.69

= 0.181

so your answer will be 2.69 + or - 0.18 g cm^-3

I HOPE U GET IT!!!

AND IF U HAV ANY ODER PROBLEMS U R FREE 2 ASK

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M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

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yup except the 2002 papers i'll check out the others cuz i dun't hav 20002

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

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oct/nov 2003

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

c)i)in string S2 force moves to the left ans in string S1 force moves to the right (i can't help u here u hav to imagine it)

ii)1)the centre is the pivot so you have to find moment from the pivot =F x s = 150 x 0.3=45Nm

ii)2)the torque is one of the two forces on the parallel sides which is 150 x 0.3 the distance =45Nm

ii)3)45=F x 0.12 , F=375N

i had done all the steps i just dont know why u calculated this : δ d = 0.0672 × 2.69d=m/v

d=m/length^3

d=580/6.0^3

d=2.69 g cm^-3

for uncertainty:

d=m/length^3

δ d/d = δ m/m + 3 δ l/l

= 10/580 + 3 × 0.1/6.0

= 0.0172 + 0.05

δ d/d = 0.0672

δ d = 0.0672 × 2.69

= 0.181

so your answer will be 2.69 + or - 0.18 g cm^-3

I HOPE U GET IT!!!

AND IF U HAV ANY ODER PROBLEMS U R FREE 2 ASK

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i didn't get MJ 04 EITHER

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

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when u add 0.0172 and 0.05 u get 0.067 which is not the uncertainty it is wat u actually get after calculating the uncertainty of the density which is 0.18/2.69=0.067 so lets take 0.18 as w so w=2.69 x 0.0067=0.18i had done all the steps i just dont know why u calculated this : δ d = 0.0672 × 2.69

yeh i get dat.. But when we used the formula δ d/d = δ m/m + 3 δ l/l didnt we take the uncertainty out of density. Or did we not?when u add 0.0172 and 0.05 u get 0.067 which is not the uncertainty it is wat u actually get after calculating the uncertainty of the density which is 0.18/2.69=0.067 so lets take 0.18 as w so w=2.69 x 0.0067=0.18

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to get the total uncertainty of the whole not only densityyeh i get dat.. But when we used the formula δ d/d = δ m/m + 3 δ l/l didnt we take the uncertainty out of density. Or did we not?

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for oct/04

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

you just add 4+4 percentage uncertainty of diameter cuz u square the diameter in finding the area

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Can someone please help me with this question. It's a very small question. Question 5c(i) they haven't told us the directions?post yourand i'll try and clear them

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_qp_21.pdf

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_ms_21.pdf

Thank you very much!

and

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_qp_23.pdf

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M/J 05- 5c, 6b(iii)

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c

5c)as the lines spread they keep going far apart and the farther apart they go the less bright they become

6b(iii)couple is force x distance so now the force is at an angle of 35 so we resolve it so it will be 2.4x10^-12 * sin35 * 2.5x10^-3

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in fig 6.1 there is 1 node and that is where sound is heard and in fig 6.2 sound is heard at the other node which is 32.4cm awayHow do we know how many nodes are there in a tube?

mj 06 question 6

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the left circle will have the positive sign and the right circle will have the negative sign as it always moves from higher potential to lower potentialCan someone please help me with this question. It's a very small question. Question 5c(i) they haven't told us the directions?

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_qp_21.pdf

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_ms_21.pdf

Thank you very much!

and

Please help me with this question In physics paper 23, question 2 part (c). I have no idea about vector triangles.

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_qp_23.pdf

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I HOPE U GOT WAT I TOLD U!!!

M/J 02- 7b

O/N 02- 9b, 2c

O/N 03- 3 c

M/J 04- 1b

O/N 04- 1b (ii)

M/J 05- 5c, 6b(iii)

O/N 05- 3c