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Potentiometer concept

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I don't understand how we use the potentiometer to measure the e.m.f of a cell
I've been surfing the net, all I can find are articles stating how the e.m.f is determined practically, but I haven't found sufficient theory detail.:(
If someone could explain it I would be grateful.(y)
 
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its a device used to compare potential differences. it consists of a metre length of resistance wire stretched horizontally between two points. a driver cell is connected across the length of the wire.
Ex = AY / AB into Eo

EX being the cell of which emf is not known
AY being the jockey length connected to galvanometer, the deflection will be zero when potential difference across AY length of wire will be equal to the potential difference of driver cell.
Ab is the total length of wire which is 1 m.
Eo is the driver cell voltage.
 
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its a device used to compare potential differences. it consists of a metre length of resistance wire stretched horizontally between two points. a driver cell is connected across the length of the wire.
Ex = AY / AB into Eo

EX being the cell of which emf is not known
AY being the jockey length connected to galvanometer, the deflection will be zero when potential difference across AY length of wire will be equal to the potential difference of driver cell.
Ab is the total length of wire which is 1 m.
Eo is the driver cell voltage.
Yes yes that's all fine and good but it still doesn't explain what's happening inside the whole circuit, i.e what is the theory behind everything you stated.
 
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Dude that's stuff on the potential divider, I need stuff on the potentiometer: specifically on how to use it to find unknown e.m.fs (the theory behind that, anyway)
Basically the same thing...
Potentiometer is used as a voltage divider...
 
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Yes yes that's all fine and good but it still doesn't explain what's happening inside the whole circuit, i.e what is the theory behind everything you stated.
when a potentiometer is balanced, no current flows from the cell being investigated. this means that its terminal p.d is equal to its emf. we do not have to worry about the lost volts. this is an advantage then a potentiometer has over a voltmeter which must draw a small current in order to work.
feeling better ? :p
 
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when a potentiometer is balanced, no current flows from the cell being investigated. this means that its terminal p.d is equal to its emf. we do not have to worry about the lost volts. this is an advantage then a potentiometer has over a voltmeter which must draw a small current in order to work.
feeling better ? :p
Absolutely not; you took that straight out of a book and explains nothing I don't already know.
I need stuff like "why is the current in the test cell zero.." etc
Any other book?
Quite a lot actully
Longman Advanced Level Physics
Cambridge AS and A2 Physics Coursebook
A level Physics by Nelkon and Parker
AS/A level Physics by Chris Mee and others (Hodder Education)
Notes from Tom Duncan's A level Physics( Teacher gave them to us)
 
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oh then i am sorry. i can't really go deep into this now. when you understand it share with me as well. :)
 
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I don't understand how we use the potentiometer to measure the e.m.f of a cell
I've been surfing the net, all I can find are articles stating how the e.m.f is determined practically, but I haven't found sufficient theory detail.:(
If someone could explain it I would be grateful.(y)
The use of a potentiometer is identical to that of a voltmeter and when used to measure the p.d between two points ,the terminals are connected as positive and negative terminals of a voltmeter.The sliding contact is tapped along the slide wire AB until the centre zero galvanometer is balanced. Then,e.m.f of the cell, E=p.d across the length.
 
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