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Probability question.

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Please someone solve this for me. Its a book question and i only have the answer 0.061.
Here's the ques:
"It is known that 24% of the customers in a bank holding a current account also have another type of account with the bank.
Calculate an approximate value for the probability that fewer than 50 customers in a random sample of 250 customers with a current account also have another type of account."
Plz help!
 

PlanetMaster

XPRS Administrator
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Let N be the number who have another type of account.
∴N ~ binomial(250,0.24) ≈ N(60, 45.6) = N(60,6.753²) (² is square not z)
= P(N < 50) →P(N < 49.5) with continuity correction
= P(Z < (49.5 - 60)/6.753 = -1.55) = 1 - 0.93943 = 0.061

Clear?
 
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