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Pure Maths 12 today........

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the vector part 2 was a bit tricky as i equated 6k^2-10k+4 to 0 instead of 1 so ill prob get 2 out of 4, i spent like 15 minutes on that part and got nowhere but 1 comment on this thread made me realise i have to equate to 1 :( and the other people from my centre found the paper tricky so dont be surprised if the GT is like 56-58 for an A. (BTW this is from Zambia).
 
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1) a=2
2) x>=-3 , x>=1
3) area=975
4) k=-1 P(-2,1)
5) C(13,7)
6) y= 15, 75
7) angle=24.1
8) a=32 sum to infinty=128 , n=18
9) volume=9pie
10) c=1
11) 76.3 and perimeter 35.1

Those are the answers i remember
 
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what did u guys get as the co-ordinates of c? you had to find the intersection of BC and AC right?
 
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How many of you proved the question with the area of the playground ? I guess it was 3. i). I forgot the question know but I guess we were supposed to show A = bla bla bla ! How did you got it ?
i think it was
A= x^2 - 30x + 1200
as for how to get it
A= 2400 - [(0.5)(40)x) + (0.50)(2x)(60-x) + (0.5)(40-2x)(60)]
if you need further explanation, id be glad to help :D
 
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Does anyone knows what was the question of trigonometry's second part ? Was it cos2y = 3tan2y or some thing else ?
 
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1) a=2
2) x>=-3 , x>=1
3) area=975
4) k=-1 P(-2,1)
5) C(13,7)
6) y= 15, 75
7) angle=24.1
8) a=32 sum to infinty=128 , n=18
9) volume=9pie
10) c=1
11) 76.3 and perimeter 35.1

Those are the answers i remember
All your answers are correct but I can't remember 1 as the value of C,if I m not wrong it was the question where we had to find the eq through integration.I think c was 2 maybe
 
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