Pure Maths 12 today........

[elbeyon]

i think it was cos^2(2y) = 3tan(2y) , although i still think there was a number before cos^2, maybe not

And do you remember the values of y that you obtained ?

 

[tanmaydube]

i got 15 and 165 i guess.

And do you remember the values of y that you obtained ?

 

[tanmaydube]

I guess guys we need to strive hard for the next component paper M1/S1 to ensure a better grade.

 

[doorman1995]

i have a doubt what was the function f-1 f inverse in ques 2 past a n is concept of third derivative in alevels syllabus?

 

[mehdi1028]

1) a=2
2) x>=-3 , x>=1
3) area=975
4) k=-1 P(-2,1)
5) C(13,7)
6) y= 15, 75
7) angle=24.1
8) a=32 sum to infinty=128 , n=18
9) volume=9pie
10) c=1
11) 76.3 and perimeter 35.1

Those are the answers i remember

Yea me 2... I was not able to Q11. part in which you had to show that x=7.218

 

[mehdi1028]

Does anyone knows what was the question of trigonometry's second part ? Was it cos2y = 3tan2y or some thing else ?

I only remeber the answers... one was 15 degree and the other75 degree!!

 

[mehdi1028]

Yeah........ Q 10 and 11 REALLY had me going though......

Q11 part 1 was a little bit tricky!! will loose 4 marks !!

 

[elbeyon]

Q11 part 1 was a little bit tricky!! will loose 4 marks !!

Yeah and part iii) was also tricky I managed to solve part i) but was not able to solve part iii) due to the time limit. Both of the questions were tricky but once you get the concept of tangent and angle perpendicular both of the questions could be solved with just few lines of calculations. Now I realize how easy the part iii) was. My luck !

 

[Nishii]

i think it was cos^2(2y) = 3tan(2y) , although i still think there was a number before cos^2, maybe not

its 2cos2y=3tan2y, for O<y<180!

 

[mehdi1028]

Yeah and part iii) was also tricky I managed to solve part i) but was not able to solve part iii) due to the time limit. Both of the questions were tricky but once you get the concept of tangent and angle perpendicular both of the questions could be solved with just few lines of calculations. Now I realize how easy the part iii) was. My luck !

Last two parts were easy dude...
how did u do the first part???

 

[elbeyon]

Last two parts were easy dude...
how did u do the first part???

The first part was also easy. You first need to state the angle touching the tangent and the center of the full circle ( i.e the circle with center C ). Then you need to find out the two sides of the right angled triangle as 20 - x and x ( Here x is the radius of the full circle and 20 is the radius of the sector ). Then you need to use sin ( given angle/2) = x/(20 - x ) (i.e sin(angle) = p/h ). Then the value of x will come correctly. And the third part was also so easy but I realized how easy it was just after handing my paper to the officials. Bad luck !

 

[mehdi1028]

The first part was also easy. You first need to state the angle touching the tangent and the center of the full circle ( i.e the circle with center C ). Then you need to find out the two sides of the right angled triangle as 20 - x and x ( Here x is the radius of the full circle and 20 is the radius of the sector ). Then you need to use sin ( given angle/2) = x/(20 - x ) (i.e sin(angle) = p/h ). Then the value of x will come correctly. And the third part was also so easy but I realized how easy it was just after handing my paper to the officials. Bad luck !

l


OK ... But Do you remember the values?
was x = 7.218 ... angle 2.1 rad and radius of sector 20cm??

 

[mehdi1028]

The first part was also easy. You first need to state the angle touching the tangent and the center of the full circle ( i.e the circle with center C ). Then you need to find out the two sides of the right angled triangle as 20 - x and x ( Here x is the radius of the full circle and 20 is the radius of the sector ). Then you need to use sin ( given angle/2) = x/(20 - x ) (i.e sin(angle) = p/h ). Then the value of x will come correctly. And the third part was also so easy but I realized how easy it was just after handing my paper to the officials. Bad luck !

I wasted last like 15 minutes on it and wasn't able to solve it...

 

[Gunner7]

Yeah..... i thought it out on the same lines! and what minimum value did you get?

3 I guess

 

[elbeyon]

l


OK ... But Do you remember the values?
was x = 7.218 ... angle 2.1 rad and radius of sector 20cm??

Other values are correct but I don't think angle was 2.1 rad. I forgot the angle now but I don't think it was 2.1.

 

[hussamh10]

To prove that it is a minimum and not a maximum, remember, they are asking for the minimum of the GRADIENT and NOT the curve

dude it is the second derivative we use to find that for the value of x either the gradient is negative or positive why would you differentiate it third tym ???

 

[hussamh10]

Other values are correct but I don't think angle was 2.1 rad. I forgot the angle now but I don't think it was 2.1.

it was 1.2

 

[hussamh10]

1) a=2
2) x>=-3 , x>=1
3) area=975
4) k=-1 P(-2,1)
5) C(13,7)
6) y= 15, 75
7) angle=24.1
8) a=32 sum to infinty=128 , n=18
9) volume=9pie
10) c=1
11) 76.3 and perimeter 35.1

Those are the answers i remember

Yeah bro alright same answrs

 

[hussamh10]

no i

All your answers are correct but I can't remember 1 as the value of C,if I m not wrong it was the question where we had to find the eq through integration.I think c was 2 maybe

no it was 1 confirm

 

[hussamh10]

i have a doubt what was the function f-1 f inverse in ques 2 past a n is concept of third derivative in alevels syllabus?

there was no need of third derivative second derivative was all what was required