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A question came on like shade box in M/J O level CIE 2012, paper 1. its the First question how do I do that? :S
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i dont get it man, -__- how did u do it? like whats the techniqueHaving a rotational symmetry of order 2 means that while rotating the diagram in a clockwise of 360 degrees (or anti clockwise for it matters),
you should get the starting image twice.
In this question the diagram is basically lyk this
http://oi49.tinypic.com/2yzj448.jpg
so you gotta shade 2 squares such that when you rotate the square 360 degrees you get the exact starting image twice
so it shld be lyk that
http://oi48.tinypic.com/2crneky.jpg
after a rotation of 180degrees, you will get the first similar image, and after 360 degrees you get the second one
Hope it helped![]()
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i dont know any such formula srryi dont get it man, -__- how did u do it? like whats the technique
Any formula for this?
I'm so formula-based public, maybe thats why I do bad in maths-d but excellent in add maths
any link to understand this chapter?I'm pretty sure theres no formula for such questions... You better just try your best to understand the question and scenario... its not that hard once you get it
A question came on like shade box in M/J O level CIE 2012, paper 1. its the First question how do I do that? :S
just keep rotating the image till you get the one yu had in the start. then just write down the number of times u rotated nd gott the figure. As in if yu rotate it twice your getting the original figureA question came on like shade box in M/J O level CIE 2012, paper 1. its the First question how do I do that? :S
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