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SOS for Physics P1

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2,884
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415
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93
q23
one wave completes at 50 m
and speed is 8
so u get time
using speed = distance/time
time is 6.25s
u get frequency
ie 1/time
so u get 0.16
now put in the eqaution
lemme know
i am waiting for ur response
 
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q25
use d sin angle = n lambda
put angle ( tetha ) as 45 and n as 3 and u get an equation making d the subject
now for highest order
angle should be 90 degrees
u need to remember this
put angle as 90 and make d the subject again
now u get two euqions
slove em
solve it by the method that they both r equal
 
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i am gettin a weird answer for 23...not one of the options and for 25 what shud i use for lambda
 
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2,884
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ok for q23
after the steps i wrote
u do it this way
u get freuency as 0.16
now find v max
ie 2 x pi x amplitude( which is 2 from graph) x freq
ke max is
half x m x v^2
ull get 4mJ
 
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