statistics 2: post your doubts and solve mine! lol

[redapple20]

Problem. Solved!))))))

 

[redapple20]

I'm gonna b back here soon!

 

[2pac]

mean for 70 times= 70*3.5. variance=70*35/12
Use SD and Mean to get probability from the normal distribution table.

hey could you please help me with some s2 doubts.Can't seem to understand q2 part i of 2009 72.Please reply whenever you can.
thanks

 

[OakMoon!]

hey could you please help me with some s2 doubts.Can't seem to understand q2 part i of 2009 72.Please reply whenever you can.
thanks

I don't take S2. I just knew how to do that question because I take further maths.

 

[2pac]

I don't take S2. I just knew how to do that question because I take further maths.

oh ok,thanks anyways.

 

[redapple20]

U do take s2 ryt?

 

[kagome]

hi can u explain me M/J 2010 73 Q2 (iii) plz? thx

 

[redapple20]

Yes I saw the Q wat cant u understand? Man says its greater than. 7 and here mean is not given but probability is given
So we wont convert it to z like we always do and also take 0.05 to b as it is Cu's this too is a probability!

 

[kirashinagami]

Hey redapple, i want to Ask you about hypothesis test, like justifying a given condition.

How can u determine whether a claim is justified when statistic test z value that we found is either larger or smaller than the significance level in one tail or two tail test? I have watched videos and read books but still dont understand!

 

[redapple20]

For example its a 1 tail test significance level 5% we 1-0.05 ans cums 0.95 we read reverse table on that. In this case its 1.645 for eg a man claims there r more than 3 ppl from a batch of 5 ppl who pass a test we need to c if it is less than that so we will take out z at tat value
and see if its less than 1.645 if its less we reject his claim if more accept

 

[kirashinagami]

For example its a 1 tail test significance level 5% we 1-0.05 ans cums 0.95 we read reverse table on that. In this case its 1.645 for eg a man claims there r more than 3 ppl from a batch of 5 ppl who pass a test we need to c if it is less than that so we will take out z at tat value
and see if its less than 1.645 if its less we reject his claim if more accept

Thank you apple!
So its what I get :
In one tail test, if the z test is less than the significant lvl, we reject it
If its more, then we accept it.
1. Am i right?


2. Does this also applies for two tail test? If its more, then we accept. If its less, then we reject?


Thanks before!!!

 

[kirashinagami]

And by the way, How to determine whether the value of the sample we got is 'significant' or 'not significant' to our null hypo?

 

[redapple20]

Thank you apple!
So its what I get :
In one tail test, if the z test is less than the significant lvl, we reject it
If its more, then we accept it.
1. Am i right?


2. Does this also applies for two tail test? If its more, then we accept. If its less, then we reject?


Thanks before!!!

Ur welcum if its 1 tail and sig level for eg 1% then z= 1- 0.1 Cal the reverse table at 0.9 if two tail 1- (0.1/2) 0.95.

 

[redapple20]

For example its a two tail at sig level 5% then z would be 1-(0.05/2)=0.975 reverse table at this value is 1.96 so we form a range
Ie if the claim is to b accepted the z that we calculate frm the formula ie z= xbar-mean/(sd/root of n) should lie btw the values ie
should b greater than -1.96 less than 1.96

 

[redapple20]

hi can u explain me M/J 2010 73 Q2 (iii) plz? thx

is the answer 90?

 

[redapple20]

Can someone explain may June s11 qp 72 Q3 c!

 

[kagome]

is the answer 90?

Nope. The answer is 8%.

 

[kagome]

Can someone explain may June s11 qp 72 Q3 c!

P(at least 1) = 1 - P(X=0)
= 1 - (e^-1.8)
= 0.8347

Next 10 match is independent of each other. Independent cases have to be multiplied.
Its like P[first match] x P[second match] x .......... P[tenth match]
since all the prob of goal in each match is the same
so it is (0.8347)^10

 

[kagome]

Can u help with me with M/J 2010 71 Q7(i). How to find probability of type 1 error? Thx

 

[redapple20]

But 1.8 is for 1 player everly Rogers. Its now asking about the whole team!