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It's same thing what you apply in binomial question. Applying 4C2 here means that from 4 turns in which turn he'll get exactly 2 unwrapped biscuitsHow did you do it?
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It's same thing what you apply in binomial question. Applying 4C2 here means that from 4 turns in which turn he'll get exactly 2 unwrapped biscuitsHow did you do it?
Oh lol sorry.its the correct method. multiply by 4C2 or by 4!/(2!*2!). as there r two wrapped and two unwrapped
yes, i'm sure. I checked this method from marking scheme for without replacement questions.
It's not. You're supposed to multiply the entire thing by 4!/2! instead of 4C2.
Isn't 4!/2! and 4C2 both equal to 6?
nope.... 4!/2! is 12 not 6![]()
Yeah, my bad but a lot of people who did this question by probability or by drawing a tree diagram got the same answer.
Yes, it is indeed correct. The correct answer was supposed to be 0.368, and it gives exactly that.
I made a horrendous error. What I did was write 4C2*(18/30)*(17/29)*(12/30)*(11/29) and got the answer 0.320. I must have been blind or something. Do you expect I'd get any marks out of 4? 2 maybe?
i got the answer 5514.. i wonder who is correct...was ans to q1 was something like , 2154?
Okay i don't remember exactly but it could be something similar to you..i got the answer 5514.. i wonder who is correct...
What did you get for the standard deviation?
Was it 6.06025?
it is 5508.5 or 5509smthng like that
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