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I'm not sure , but i was confident about this question
GoOd
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I'm not sure , but i was confident about this question
Which question q 2?yaar wo binomial walay ka 0.999 nai hay?
yeah i think!! jis may p was 0.65Which question q 2?
ye wala mene aisa he kya hay/ but m asking about jis may greater than 2 but less than 12 ki pr find karni thii don't remember this one , you are asking about expected value right? I remember Y had values O, 2, 4 - probablities 0.48 , 0.42 and 0.1 maybe
yeah thats rYt!!i did like 1 - p(x=2)-p(x=1)-p(x=0)-p(x=12). Don't remember final answer
No i think i didnot subtract the pr of 12! Tau ub meray out of 3 ktney aen gay?i guess my value was 0.993 , you must rounded off all the values may be that's why your answer was 0.999
I think 2 asktey hein , not sure ..No i think i didnot subtract the pr of 12! Tau ub meray out of 3 ktney aen gay?
Hmm Appk tau 50/50 anay hainI think 2 asktey hein , not sure ..
yei Tough questions thay i guess!! Mine m1 was flop... p3 ok that p1 good! n s1 may b 47 a he jaen gayDua karo , haven't discussed the whole paper , my P3 was realllyyyyy bad ,
I gave p1 and M1 last year , got A. S1 was good. But p3 , not sure , left a question of around 4 marks and had many answers wrongyei Tough questions thay i guess!! Mine m1 was flop... p3 ok that p1 good! n s1 may b 47 a he jaen gay
oh yes exactly 2 unwrapped ya wrapped biscuit lene thay from 4 i guess , I did like 4C2 * 18/30 * 17/29 *12/28*11/27
It's not. You're supposed to multiply the entire thing by 4!/2! instead of 4C2.Are you perfectly sure this method is valid?
How did you do it?i did the long way and got the same answer as yours i think am relieved
its not u had to subract 12 also because it was between 3 and 12 with excluding 3 and 12R u sure?? I subtracted the probability of 0,1,2 from 1....its not ryt?
its the correct method. multiply by 4C2 or by 4!/(2!*2!). as there r two wrapped and two unwrappedIt's not. You're supposed to multiply the entire thing by 4!/2! instead of 4C2.
yes, i'm sure. I checked this method from marking scheme for without replacement questions.Are you perfectly sure this method is valid?
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