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It is binomial distribution...
So X is binomially distributed with n and p
So mean = np and variance = npq
Your job is to find n and p...
I gave you the hint..
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It is binomial distribution...
please splve this qs!!It is binomial distribution...
So X is binomially distributed with n and p
So mean = np and variance = npq
Your job is to find n and p...
I gave you the hint..![]()
yehi to nae samajh a raha keh kia n loon or kia p???It is binomial distribution...
So X is binomially distributed with n and p
So mean = np and variance = npq
Your job is to find n and p...
I gave you the hint..![]()
within 1 standard deviation of the mean ka matlabb??It is binomial distribution...
So X is binomially distributed with n and p
So mean = np and variance = npq
Your job is to find n and p...
I gave you the hint..![]()
Within 1 SD means the same as I explained b4...within 1 standard deviation of the mean ka matlabb??
do mj 14 paper 61 then tell meWithin 1 SD means the same as I explained b4...
It means P(mean-SD<X<mean+SD) ...
Got itttt..........?
i know how to do this.its easyPLZZZ TELL (ii)b !!!
Nine cards are numbered 1, 2, 2, 3, 3, 4, 6, 6, 6.
(i) All nine cards are placed in a line, making a 9-digit number. Find how many different 9-digit
numbers can be made in this way
(a) if the even digits are all together, [4]
(b) if the first and last digits are both odd. [3]
(ii) Three of the nine cards are chosen and placed in a line, making a 3-digit number. Find how
many different numbers can be made in this way
(a) if there are no repeated digits, [2]
(b) if the number is between 200 and 300
The given 1...do mj 14 paper 61 then tell me
i hav tried ur method....
we do hav to divide by s.d
mean - sd,which s.d ,the one given i.e 1.345 or 1 sd??
do we hav to divide it by sd too??The given 1...
u r sayin if mean is 23,then 23-1<X<23The given 1...
no one will tell u,every 1 is doin their own work,so ...A box contains five balls numbered 1, 2, 3, 4, 5. Three balls are drawn randomly at the same time
from the box.
(i) By listing all possible outcomes (123, 124, etc.), find the probability that the sum of the three
numbers drawn is an odd number. [2]
The random variable L denotes the largest of the three numbers drawn.
(ii) Find the probability that L is 4. [1]
(iii) Draw up a table to show the probability distribution of L. [3]
(iv) Calculate the expectation and variance of L.
i know the answers to the questions you posted..but isnce your not willing to help i will also notabdul moeed rana said:same problems here,dont know wat to do in these qs
hahahaha,its okayi know the answers to the questions you posted..but isnce your not willing to help i will also not
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