Statistics S1 Doubts

[abdul moeed rana]

i know the answers to the questions you posted..but isnce your not willing to help i will also not

wat i said above ,its true.

 

[Evil Philanthropist]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_63.pdf

Guys help!
In Q(5) (iii) when finding the value of k, why does z>0.445 become P(z<k) - P(z<0.445) in the next step? I mean, why is it becoming <0.445 when it should >?
Is there any technique or explanation I am missing?

 

[abdul moeed rana]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_63.pdf

Guys help!
In Q(5) (iii) when finding the value of k, why does z>0.445 become P(z<k) - P(z<0.445) in the next step? I mean, why is it becoming <0.445 when it should >?
Is there any technique or explanation I am missing?

take in easy man or woman,...u'll ace the exam,do say ur prayer in the morning

 

[Evil Philanthropist]

take in easy man or woman,...u'll ace the exam,do say ur prayer in the morning

I am girl. A guy wouldn't have that dp. <.<
LOL, thanks, Insha'Allah. I am chill, I just want to know this. These types of questions are repeated and I don't even know the process.

 

[abdul moeed rana]

I am girl. A guy wouldn't have that dp. <.<
LOL, thanks, Insha'Allah. I am chill, I just want to know this. These types of questions are repeated and I don't even know the process.

may be because minus signs cancel out,thus sign changes

 

[Keirad]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_63.pdf

Guys help!
In Q(5) (iii) when finding the value of k, why does z>0.445 become P(z<k) - P(z<0.445) in the next step? I mean, why is it becoming <0.445 when it should >?
Is there any technique or explanation I am missing?

P(87<X<k) = 0.3
P(X<87) = 0.6718 (From the previous question)
P(X<k)= P(X<87) + P(87<X<k) = 0.6718+ 0.3= 0.9718
P(Z<=(k-82)/root 126) = 0.9718
(k-82)/root 126 = 1.906 or (1.907)
k-82= 21.4
k= 103.39= 103 (3sf)

AND it was never greater than it is less than. Read the question again.

 

[mnotanerd]

we

P(87<X<k) = 0.3
P(X<87) = 0.6718 (From the previous question)
P(X<k)= P(X<87) + P(87<X<k) = 0.6718+ 0.3= 0.9718
P(Z<=(k-82)/root 126) = 0.9718
(k-82)/root 126 = 1.906 or (1.907)
k-82= 21.4
k= 103.39= 103 (3sf)

AND it was never greater than it is less than. Read the question again.

we dont have to find see normal table for k value?? i mean 0.3??

 

[Crimson-Saint]

how was P62 guys?

 

[abdul moeed rana]

i found q 1-4 difficult,managed to do q3 n 4 n 2. q5-7 were easy.q1 was ....difficult

 

[abdul moeed rana]

post your answers.

 

[abdul moeed rana]

same here bro..but i actually found the first 1 easy..no. 3 and 4 was tough :/

u did in q1 1c1 * 1c1 * 48c43??in q1
post ur ans

 

[abdul moeed rana]

same here bro..but i actually found the first 1 easy..no. 3 and 4 was tough :/

i did this q1 ^.hope its right

 

[Keirad]

These were the most easiest permutation combination questions i had ever solved

 

[abdul moeed rana]

These were the most easiest permutation combination questions i had ever solved

your answers?

 

[Keirad]

1st- 48c43
5! x 6!
7P4 x 6!

 

[mnotanerd]

why

1st- 48c43
5! x 6!
7P4 x 6!

7p4?? my baqi are same

 

[abdul moeed rana]

why

7p4?? my baqi are same

in q1 instead of using 1c1 * 1ci ,i did 2c2?this is all correct!??

 

[mnotanerd]

in q1 instead of using 1c1 * 1ci ,i did 2c2?this is all correct!??

no 2c2 galat hai

 

[B!(+)(+)dy $k(_)!!]

1st - 48C43
2nd - 6! x 5!
- 6! x 7P4
3rd - 1/324
- 0.0212
4th - Tree diagram
- E(X) = 2 attempts
5th - P(X<8) was easy to find
- q was 7.74
- P(X<4 mean) = 1 - P(X<2)
6th - cumulative frequency graph
- h = 15.6 cm or 21.5 cm (not sure)
- SD = 6.01
7th - binomial distribution (4<=X<=6)
- Normal distribution P(X<114.5) dont remember
- np > 5 and nq >5

 

[Crimson-Saint]

omg yes i got 1 wrong but 2 was all correct al7amdulillah and what did u guys get for cmmulative freqency height? i got 16cm