Transformation (Maths)

[Chicharito]

Hey guys, I'm facing some problems in Transfromation.
Can anyone tell me the basics of rotation?
And please tell me how to find the Stretch and Scale factors.

 

[ibadsiddiqi]

to find the scale factor for stretch, if A*is the image of A then the scale factor is (distance of A* from the invarient line) divided by the (distance of A from the invarient line)

 

[ibadsiddiqi]

BTW i hate transformations!!!

 

[zain786]

we all ahte it!!!!!!!!!!!!!!!

 

[ibadsiddiqi]

haha. Atleast it wont come in p2 this year. A 12 mark question on transformations came last year in november!

 

[Maleeha]

haha. Atleast it wont come in p2 this year. A 12 mark question on transformations came last year in november!

i had it done so well..

 

[ibadsiddiqi]

But it will definetly come in p1!! it always comes in p1 and its usually worth 4 or 5 marks!

 

[ibadsiddiqi]

Q.20 http://www.xtremepapers.me/CIE/Cambridg ... 9_qp_1.pdf

 

[Silent Hunter]

ibadsiddiqi u want help in it or just refering to it ?

 

[ibadsiddiqi]

I want help in it

 

[Maleeha]

cud anyone help me in q.25 part (b) http://www.xtremepapers.me/CIE/Cambridg ... _qp_12.pdf

 

[ibadsiddiqi]

first you find the acceleration from 0-20. the deceleration will therefore be half of that. Now the car took 20 seconds to achieve a speed of u m/s. and the acceleration was twice of the deceleration so it would take 40 seconds to get a speed of u/2 and hence 80 seconds to get a speed of u/4. I think 80 seconds is the answer

 

[zain786]

haha. Atleast it wont come in p2 this year. A 12 mark question on transformations came last year in november!

WHY WON;T IT COME THIS YEAR???

 

[ibadsiddiqi]

I dont know if it will come or not but i THINK it wont come cuz it already came in the october/november session and transformation questions dont come that often in Paper 2. However they do come often in Paper1

 

[zain786]

OH RYTE

 

[Maleeha]

first you find the acceleration from 0-20. the deceleration will therefore be half of that. Now the car took 20 seconds to achieve a speed of u m/s. and the acceleration was twice of the deceleration so it would take 40 seconds to get a speed of u/2 and hence 80 seconds to get a speed of u/4. I think 80 seconds is the answer

the answer's 90

 

[ibadsiddiqi]

now i am confused

 

[ibadsiddiqi]

I think i got it. The time taken for the car to come to rest when it starts decelerating is 40 seconds. so the time taken for the car to come to a speed of U/4 is 3/4 x 40. So the time taken for the car to achieve a speed of U/4 is 30 seconds. So the time t is 60 + 30= 90!!! YES I AM A GENIUS.

Did you get it?? I could explain it further if you want me to

 

[Maleeha]

ahhh... yes u r a genius.. thankyou so much... i got it

 

[ibadsiddiqi]

you are welcome. If you have anymore questions, dont hesitate to ask!