Winter 2015 papers er

[nehaoscar]

Hey does anyone have the examiner reports to the winter 2015 papers for the following subjects?
Maths (9709), Physics (9702), Chemistry (9701), Biology (9700), English (9093)
If not does anyone know when they're gonna be released?

 

[muhammadali233]

Hey does anyone have the examiner reports to the winter 2015 papers for the following subjects?
Maths (9709), Physics (9702), Chemistry (9701), Biology (9700), English (9093)
If not does anyone know when they're gonna be released?

I am still not able to found those,cie must have released it by now.Anyone?

 

[TRAMANZ]

Hi There,
Please do u have the oct/nov 2015 papers for bio, chem nd phy?
If u have can u pls send it to [email protected] or [email protected]
Thank you\

 

[Akshajistari]

Hey does anyone have the examiner reports to the winter 2015 papers for the following subjects?
Maths (9709), Physics (9702), Chemistry (9701), Biology (9700), English (9093)
If not does anyone know when they're gonna be released?

Apparently, they come out in March.

 

[nehaoscar]

Apparently, they come out in March.

Ohh thats late :/ thanks though

 

[nehaoscar]

Hi There,
Please do u have the oct/nov 2015 papers for bio, chem nd phy?
If u have can u pls send it to [email protected] or [email protected]
Thank you\

they're on gceguide.com

 

[Akshajistari]

Ohh thats late :/ thanks though

You're welcome

Could you please answer this question: no one has responded

The answer is B. But how?

 

[Eugene99]

You're welcome

Could you please answer this question: no one has responded
View attachment 59448
The answer is B. But how?

Using the equations of half reactions, we have:
5(Sn2+ --> Sn4+ + 2e-)
2(8H+ + MnO4^- + 5e- --> Mn2+ + 4H2O)
------------------------ -------------------------- -----------------
16H+ + 5Sn2+ + 2MnO4^- --> 5Sn4+ + 2Mn2+ + 8H2O

No. of mol of SnCl2 = 9.5/190 = 0.05 mol
using the ratio 2:5 from the equation above
(0.05x2) /5 = 0.02 mol

 

[iSean97]

You're welcome

Could you please answer this question: no one has responded
View attachment 59448
The answer is B. But how?

 

[Akshajistari]

Using the equations of half reactions, we have:
5(Sn2+ --> Sn4+ + 2e-)
2(8H+ + MnO4^- + 5e- --> Mn2+ + 4H2O)
------------------------ -------------------------- -----------------
16H+ + 5Sn2+ + 2MnO4^- --> 5Sn4+ + 2Mn2+ + 8H2O

No. of mol of SnCl2 = 9.5/190 = 0.05 mol
using the ratio 2:5 from the equation above
(0.05x2) /5 = 0.02 mol

Thank you so much!

 

[Akshajistari]

Thank you so much!
If you don't mind me asking, where did you get that explanation?

iSean97

 

[iSean97]

Thank you so much!
If you don't mind me asking, where did you get that explanation?

iSean97

I solve it myself for you.
I'm also taking M/J Exam this year for my AS and O/N for A2.

 

[Akshajistari]

I solve it myself for you.
I'm also taking M/J Exam this year for my AS and O/N for A2.

Oh cool! Thanks

I'm writing in MJ 2016 . Both AS and A2

 

[muhammadali233]

Oh cool! Thanks

I'm writing in MJ 2016 . Both AS and A2

same here and please get rid of the signature it is a little too long and annoying.

 

[TRAMANZ]

they're on gceguide.com

THANK YOU SOOOO MUCH
I LOVE U FOR THIS