YouTube Videos on Past Year Chemistry MCQs

[GCE As and a level]

Its a bit tough, cause I'm getting messages from students in this forum to help with questions. And also I have to give time to my own students.

It was just a suggestion
THANK YOU !!!

 

[kingo44]

no fk ur students just upload more papers please oi need them cmon also free radiical questions od odoo it

 

[Metanoia]

no fk ur students just upload more papers please oi need them cmon also free radiical questions od odoo it

I'm not sure if its your intention to make me less willing to carry on the project. But you are close to succeeding.

 

[not.maria]

thank you
Your videos are very helpful

 

[Browny]

I'm not sure if its your intention to make me less willing to carry on the project. But you are close to succeeding.

Metanoia please don't mind kingo44, your videos are very helpful and please continue your good work.

 

[not.maria]

Metanoia please don't mind kingo44, your videos are very helpful and please continue your good work.

yes Metanoia we really appreciate your time and effort

 

[Metanoia]

http://www.youtube.com/playlist?list=PL4Jmce8VJnNXSmX2z10ACyurQ7mWgY0fq

Video of June 2011 is uploaded.

 

[GCE As and a level]

y did u skipped 2012 and W2013 ??!

http://www.youtube.com/playlist?list=PL4Jmce8VJnNXSmX2z10ACyurQ7mWgY0fq

Video of June 2011 is uploaded.

 

[Solostar]

Thank you very much, Metanoia

Great work!

 

[Sharmin Zinia]

I need Oct/Nov 2009 p11 ASAP!!! :'(

 

[kingo44]

bro all i want metanoia is to carry on the subject lol ur awesome heloed alot

 

[saniyaaamir]

What is your username on YouTube? Because youtube is blocked in Pakistan. How do i view these videos? By what name have you uploaded them on youtube? Please reply ASAP?

 

[Metanoia]

What is your username on YouTube? Because youtube is blocked in Pakistan. How do i view these videos? By what name have you uploaded them on youtube? Please reply ASAP?

user name is meta tutor.

I'm sorry, but I'm not too sure how get around the problem that youtube is not allowed to be viewed on your side.

I'm currently working on Oct 2013 and 2009.

Not based on any request by students, but just starting with the more recent ones and working backwards on alternate years.

 

[kingo44]

thank u so much metanoia u r a life saver i swear thank u so much i ur the best upload more many peop;e r suffering includin me do moreee never stop before 10jun i need to end this

 

[GCE As and a level]

y did u skipped 2012 and W2013 ??!

user name is meta tutor.

I'm sorry, but I'm not too sure how get around the problem that youtube is not allowed to be viewed on your side.

I'm currently working on Oct 2013 and 2009.

Not based on any request by students, but just starting with the more recent ones and working backwards on alternate years.

Metanoia Its not nice to ignore people cuz ur helping them

 

[Metanoia]

Metanoia Its not nice to ignore people cuz ur helping them

not too sure I understand. What do you mean?

 

[GCE As and a level]

not too sure I understand. What do you mean?

As u got it

 

[Metanoia]

Nov 2013 P11
http://www.youtube.com/playlist?list=PL4Jmce8VJnNU4YaGfNrPYv7SBJXnB1IAC

June 2009 P1 uploaded (mistakenly typed as 2007 originally)
http://www.youtube.com/playlist?list=PL4Jmce8VJnNVom2AGZXz6fdxSnIl9G-8D

For those who messaged me to ask, I'ld like to clarify that I did not do these videos for my current students. We actually are taking a different chemistry paper from 9701.

 

[kingo44]

In some fireworks there is a reaction between powdered aluminium and powdered barium nitrate in which heat is evolved and an unreactive gas is produced.
What is the equation of the reaction
A 2Al +Ba(NO3)2 ---> Al2O3 + BaO + 2NO
B 4Al + 4Ba(NO3)2 ---> 2Al2O3 + 4Ba(NO2)2 + O2
C 2Al + 3Ba(NO3)2 ---> 5Al2O3 + 3BaO + 3N2
D 2Al + 18Ba(NO3)2 ---> 10Al(NO3)3 + 18BaO + 3N2

 

[NabzJ]

He explained it in his video, lol.
Not A or B cuz a reactive gas is produced.... and not D because Al(NO3)3 is usually formed when it thermally decomposes where as this does not and therefore the ans is C.