Physics: Post your doubts here!

[Kanekii]

Is the answer B?

 

[Hisham Khan]

Can anyone explain this?

 

[A*****]

ohhh..thank you i never knew about the switch thing
, but what did they mean when they said that a pd of 0v to its input at one switch position

I think that it is the lower one wire which is at zero potential

 

[Kanekii]

d = 100m
u = 10m/s
v = 20m/s

v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²

The distance would be 200m
D=200*

 

[A*****]

Is the answer B? View attachment 64138

No it's D

 

[Hisham Khan]

Is the answer B? View attachment 64138

yes.
Intensity directly proptional to Amplitude square and inversely to X SO I =A/X2.
AMPLITUDE 8 AT P.LET ASSUME R =1. SO 8/1=8
NOW Q =2R SO AS DISTANCE FOR P=1 DISTANCE FOR Q=2 INTO 1 =2
SO INTENSITY FOR Q=8/2=4

 

[Hisham Khan]

No it's D

Wait isint it b??

 

[Hisham Khan]

no i

The distance would be 200m
D=200*

t would be 100 as we take inital 10

 

[Hisham Khan]

yes its 4.Mistake in calculation xD.Edited it now.It should be correct

 

[Kanekii]

I think that it is the lower one wire which is at zero potential

 

[Kanekii]

no i

t would be 100 as we take inital 10

For 100
Initial is zero

 

[Hisham Khan]

no as i

For 100
Initial is zero

t passes the marker it's speed is 10 so u=10.
It can't be 0 as it is moving already.Check the calculations,you'll get correct answer which is 1.5

 

[Mush999]

Just the 14th one pls!

 

[A*****]

Wait isint it b??

 

[Kanekii]

 

[A*****]

Just the 14th one pls!View attachment 64141

Refer to the examiner report

 

[Tom Sewage]

27: The formula for path difference is (n-1/2)lamda
n=2, and you can find lamda using x=lamda(D)/a (the double slit formula)
Your lamda will turn out to be 4x10^-9 m
Now just insert the n and lamda into the path difference equation: (2-0.5)(4x10^-7)
Ans will be option C

28: For open tube/pipe, formula for lowest frequency is f=v/2L
v=fx(2L) ---- your open tube equation
For closed tube, formula for lowest frequency is: f=v/4L
v=fy(8L) ----- your closed tube equation
Solve the two equations algebraically now
fx(2L)=fy(8L)
fx=4Fy(D)

thank u

 

[Kanekii]

View attachment 64142

Ahh forgot the A^2

 

[A*****]

Is this statement regarding 1% correct?? But the extra 0.1 is 10%, not 1%

Someone plz answer this as well

 

[potatocorn12]

i am confused with both questions ugh