Physics: Post your doubts here!

[A*****]

This ?

 

[A*****]

can someone explain q 36 in paper 11 may june 2017 ...

The switch is always connected to the positive terminal of the battery so C and D are ruled out
We need a voltage between 5 and 7V so if we look at A, the output is 1/2 x 9= 4.5V which is not bw the specified range
In B the output is 2/3 x 9= 6V which is within the range so B is the correct option

 

[Hisham Khan]

The switch is always connected to the positive terminal of the battery so C and D are ruled out
We need a voltage between 5 and 7V so if we look at A, the output is 1/2 x 9= 4.5V which is not bw the specified range
In B the output is 2/3 x 9= 6V which is within the range so B is the correct option

Thanks bruh!

 

[Kanekii]

is there any other method to do this?

 

[mariam001]

The switch is always connected to the positive terminal of the battery so C and D are ruled out
We need a voltage between 5 and 7V so if we look at A, the output is 1/2 x 9= 4.5V which is not bw the specified range
In B the output is 2/3 x 9= 6V which is within the range so B is the correct option

ohhh..thank you i never knew about the switch thing
, but what did they mean when they said that a pd of 0v to its input at one switch position

 

[Hisham Khan]

View attachment 64137 is there any other method to do this?

d = 100m
u = 10m/s
v = 20m/s

v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²

 

[Kanekii]

Is the answer B?

 

[Hisham Khan]

Can anyone explain this?

 

[A*****]

ohhh..thank you i never knew about the switch thing
, but what did they mean when they said that a pd of 0v to its input at one switch position

I think that it is the lower one wire which is at zero potential

 

[Kanekii]

d = 100m
u = 10m/s
v = 20m/s

v² = u² + 2ad
so
a = (v² - u²)/(2d) = (20² - 10²)/(2*100) = 1.5m/s²

The distance would be 200m
D=200*

 

[A*****]

Is the answer B? View attachment 64138

No it's D

 

[Hisham Khan]

Is the answer B? View attachment 64138

yes.
Intensity directly proptional to Amplitude square and inversely to X SO I =A/X2.
AMPLITUDE 8 AT P.LET ASSUME R =1. SO 8/1=8
NOW Q =2R SO AS DISTANCE FOR P=1 DISTANCE FOR Q=2 INTO 1 =2
SO INTENSITY FOR Q=8/2=4

 

[Hisham Khan]

No it's D

Wait isint it b??

 

[Hisham Khan]

no i

The distance would be 200m
D=200*

t would be 100 as we take inital 10

 

[Hisham Khan]

yes its 4.Mistake in calculation xD.Edited it now.It should be correct

 

[Kanekii]

I think that it is the lower one wire which is at zero potential

 

[Kanekii]

no i

t would be 100 as we take inital 10

For 100
Initial is zero

 

[Hisham Khan]

no as i

For 100
Initial is zero

t passes the marker it's speed is 10 so u=10.
It can't be 0 as it is moving already.Check the calculations,you'll get correct answer which is 1.5

 

[Mush999]

Just the 14th one pls!

 

[A*****]

Wait isint it b??