We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Is it B?Why cant the answer be A?
Yes in this case the forward force will be taken as resultant force. ( when assuming zero resistance)
But in the case if acceleration is to be zero it will be only be if the resultant force is zero which is not in this case thus option D is not correct.
And the points you stated above are correct.
Yes. Thank you.Is it B?
If so its because the moment has to be kept constant to keep the bar in equilbrium so if x is increased then F should decrease therefore F and x would be inversely proportional
I did. Still having this confusion.
The main thing you have to focus on here is that not the ' Speed ' remains unchanged but the ' Velocity ' remains unchanged. For the acceleration to be zero the change in velocity should be zero not speed.I did. Still having this confusion.
The question implies there is 0 net force (by saying all external forces on a body cancel out which means it must be moving with constant velocity and 0 net force). When the net force is 0, by N2L there shouldnt be any change in speed as fnet=ma. Fnet=0 and 0=ma for even a reducing mass gives 0 acceleration just due to 0 net force. With 0 net force f=ma shouldnt work as an explanation for change in speed even if mass is changing.The main thing you have to focus on here is that not the ' Speed ' remains unchanged but the ' Velocity ' remains unchanged. For the acceleration to be zero the change in velocity should be zero not speed.
Thank you. I understand why C is wrong.it can be true but is NOT always.
that is why the questions says 'MUST'
I assume that u already know that gravity is always acting on the object through the motion ... therefore at its Max height u will have g acting downwards .... now let's study the horizontal component of the velocity, u will find out that the horizontal component throughout the journey stays constant even at its Max height which implies that air resistance is acting to balance the force , hence the acceleration of the horizontal component is zero n as u know air resistance act on opposite direction which in this case it's to the right as the object is moving to the left ...Need help understanding this question. D is the answer.
I hope the examination report help understand the question:Need help understanding this question. D is the answer.
https://www.google.com/search?q=for...AQ&biw=360&bih=511&dpr=2#imgrc=1Mi7aLR1qrdwYMI hope the examination report help understand the question:
Question 12
When a body is moving through air to the left, there will be a drag force acting on it to the right, as well as its weight. The answer here is D, but both A and C were more popular responses.
The site you mentioned is for projectile motion in which we assume that air resistance is negligible or equal to zero while doing our calculations.https://www.google.com/search?q=for...AQ&biw=360&bih=511&dpr=2#imgrc=1Mi7aLR1qrdwYM
It says dat only g acts on the object ....
Yes it is considered a projectile for the motion is without air resistance and it's a parabolic path.In this question, is the journey of the object between X and Y considered as projectile motion? As it follows a parabolic path.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now