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Physics: Post your doubts here!

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Ibrahim Yaqoob

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I just gave my phy paper2 in oct/nov session . It had a non rectilinear motion question in which we had to calculate max vertical displacement. I made a blunder and took the value of accelaration positive (9.81). It was of three marks i guess. the next question asked KE/GPE. so it subsequently used the height calculated in previous question . I took the other things completely fine.this was of 4 marks. Can anyone guess how much marks will I be losing?
 
Hamnah Zahoor

Hamnah Zahoor

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Raheel327
The philosophy of reaching a maximum, any maximum, means that philosophically one is climbing and climbing higher and higher to reach the maximum peak, as long as there is a higher peak one keeps on climbing the slope. Once one reaches the top, the top must be a horizontal plane, even if it is a sharp peak, it must be a plane otherwise one has not reached the maximum.
Then one goes down the peak.

So, it is the same with velocity, if the velocity reached is a maximum, one can only go down the slopes around it, after retaining that maximum velocity for some time.
Untitled.png


When acceleration is equal to zero than, F =ma a= 0 than resultant force is equal to zero.
 
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Hamnah Zahoor

Hamnah Zahoor

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Raheel327 said:
How can the acceleration be 0.20ms^-2 when the speed is still 10ms-1?
Click to expand...

As I have shown in the graph above although the acceleration begins to be 0.20 but the initial will remain 10 ms^-1 . the point where it begins it will change after wards.
 
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Mr."S"

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Is urdu,islamiyat and pak studies required for getting admission at nust
Because I have e-mailed those guys like 10 times and they don't give a proper answer.Also i have done my olevels from uae and doing a levels in pak
 
K

kfemknwnsx

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Mr."S" said:
Is urdu,islamiyat and pak studies required for getting admission at nust
Because I have e-mailed those guys like 10 times and they don't give a proper answer.Also i have done my olevels from uae and doing a levels in pak
Click to expand...
You will require those 3 subjects. Check the IBCC website though since they're the ones that create the Equivalency Form(you may get some leeway if you are a dual national).
 
Hamnah Zahoor

Hamnah Zahoor

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Clark20 said:
Need help with this.
Click to expand...
Mg - T = Ma -------(1)
T - mg = ma ------(2)

Make T subject in the second equation
T = ma + mg
substitute in first equation
Mg - (ma+mg) = Ma
Mg - ma -mg = Ma
Mg - mg = Ma + ma
(M - m)g = (M + m)a
a=(M-m)g/(M+m)
 
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Clark20

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Hamnah Zahoor said:
Mg - T = Ma -------(1)
T - mg = ma ------(2)

Make T subject in the second equation
T = ma + mg
substitute in first equation
Mg - (ma+mg) = Ma
Mg - ma -mg = Ma
Mg - mg = Ma + ma
(M - m)g = (M + m)a
a=(M-m)g/(M+m)
Click to expand...

Can you please explain more about how we can think of the tension forces 'T' acting on the masses, for better understanding? Like, how are the tension forces even exerted on the masses?
Also, is T in both masses equal in magnitude? If yes, why?[/QUOTE]
 
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