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Since we are talking in terms of power which is energy per second, we should be doing all our calculations of energy for 1 second only.
Well the volume is 1.5 x 10^4 per hour so per second the volume consumed should be
1.5 x 10^4/3600 = 4.17 cm3 <------ this is the volume consumed per second.
Now the energy transferred per second will be
4.17 x 34 = 141.7 kJ <----- it can be called the power transferred to the engine as well becuz its energy per second right?
Moving on to the power wasted.
Now the 141.7kJ is the TOTAL power.
While 40kJ is the useful power.
So to find the waste --------> total - useful = 141.7 - 40 = 101.7
Round it off to 102 kJ
Hoping it helped
thanks for solving