The correct answer I guess is AView attachment 64476 can anyone plz tell me the answer and why it is the answer
This is the explanation:
As you increase the temperature, the rate of enzyme working becomes more efficient as it reaches more towards the optimum temperature, therefore it will produce more enzyme-substrate complex and then product, but after the optimum temperature, the enzyme denatures and the active site is no more complementary to the shape of the substrate, less enzyme-substrate complex is formed and more substrate is left out.
you might confuse with D but the thing is the substrate concentration won't increase back because this reaction is not a reversible reaction and it's not like you can change the product back to the reactant so basically substrate concentration remains constant.
I hope you understood.