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Where can i find purification of copper? 

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SO2 has forms 2 bonds with each O and it has 1 lone pair...so it has 2 bond pairs and 1 lone pair...isnt it ?/hmm confused..
electrlysis? look in your book under electrolyisiWhere can i find purification of copper?![]()
2 lone pairsSO2 has forms 2 bonds with each O and it has 1 lone pair...so it has 2 bond pairs and 1 lone pair...isnt it ?/
ist permanent diple, the electronegativity difference caused by fluorine, it doesnt have h bondingHello everybody! Okay so I have a question: Does CH3F show hydrogen bonding? Because in a paper, the slightly higher boilin point of CH3F was said to be caused by it's permanent dipole. Why doesn't hydrogen bonding apply here?
no its one lone pair and it forms 2 double bonds with oxygen2 lone pairs![]()
ok S IS IN GRP VII...so it has 6 outer most e- ...if 2 of them r shared with O ..as each O needs 2 e- to complete its octate..so 2 e- r left...which is 1 line pair...isnt it/2 lone pairs![]()
But why not? Hydrogen bonding requires H and either N,O or F with a lone pair. So it should e applicable?ist permanent diple, the electronegativity difference caused by fluorine, it doesnt have h bonding
yes its 1 lone pair stop getting confusedok S IS IN GRP VII...so it has 6 outer most e- ...if 2 of them r shared with O ..as each O needs 2 e- to complete its octate..so 2 e- r left...which is 1 line pair...isnt it/
http://www.chemguide.co.uk/inorganic/extraction/copper.htmlWhere can i find purification of copper?![]()
i noooo...yes its 1 lone pair stop getting confused
Draw the structure of CH3F, and you will realize the the flourine atom isn't bonded to a hydrogen.Hello everybody! Okay so I have a question: Does CH3F show hydrogen bonding? Because in a paper, the slightly higher boilin point of CH3F was said to be caused by it's permanent dipole. Why doesn't hydrogen bonding apply here?
yeah, im so sorry, i was wrong, i had it in my notes all this time, i learnt that, just called my teacher got it correctedok S IS IN GRP VII...so it has 6 outer most e- ...if 2 of them r shared with O ..as each O needs 2 e- to complete its octate..so 2 e- r left...which is 1 line pair...isnt it/
its aryt broyeah, im so sorry, i was wrong, i had it in my notes all this time, i learnt that, just called my teacher got it corrected
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