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AS Chemistry P2 Prep.

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the sulphur makes one bond with each oxygen hence two bonds, and then sulphur has six electrons in the outer shell so the remaining is 2 lone pairs
 
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I don't have a book. I study from my teacher's notes. He told us to study from o-levels electrloysis. But i dont have the notes :cry:
 
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Hello everybody! Okay so I have a question: Does CH3F show hydrogen bonding? Because in a paper, the slightly higher boilin point of CH3F was said to be caused by it's permanent dipole. Why doesn't hydrogen bonding apply here?
 
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Because for hydrogen bonding hydrogen should be bonded to an electronegative element like N,O or F!
 
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Hello everybody! Okay so I have a question: Does CH3F show hydrogen bonding? Because in a paper, the slightly higher boilin point of CH3F was said to be caused by it's permanent dipole. Why doesn't hydrogen bonding apply here?
ist permanent diple, the electronegativity difference caused by fluorine, it doesnt have h bonding
 
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ok S IS IN GRP VII...so it has 6 outer most e- ...if 2 of them r shared with O ..as each O needs 2 e- to complete its octate..so 2 e- r left...which is 1 line pair...isnt it/
yes its 1 lone pair stop getting confused
 
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Hello everybody! Okay so I have a question: Does CH3F show hydrogen bonding? Because in a paper, the slightly higher boilin point of CH3F was said to be caused by it's permanent dipole. Why doesn't hydrogen bonding apply here?
Draw the structure of CH3F, and you will realize the the flourine atom isn't bonded to a hydrogen.
 
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ok S IS IN GRP VII...so it has 6 outer most e- ...if 2 of them r shared with O ..as each O needs 2 e- to complete its octate..so 2 e- r left...which is 1 line pair...isnt it/
yeah, im so sorry, i was wrong, i had it in my notes all this time, i learnt that, just called my teacher got it corrected
 
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