- Messages
- 44
- Reaction score
- 7
- Points
- 8
i think the last one we need to find 2 different colours which will be denoted by 4!/2!2! and as we need 2 for each colour so the 6 different colours is to be selected for 2 holes so 6c2 so the answer is 90 and then add all of the previous answers to itPart 4...hmmm. okay see there will normally be 4! arrangements if 4 diff. colors are used. since 2 are the same, we make it 4!/2!.
there are 6 colors in total, AND since u have to choose 1 peg of a specific colour only, 6x 5C2
therefore,
4!/2! arrangements * 6 colors * 5C2 pegs of diff colours = 720
part v)
im really not sure.