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and please i need help in question 6 part iv) and v) in nov 10 paper 61 ??
thnx
thnx
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usually.is it always like this??
Part 4...hmmm. okay see there will normally be 4! arrangements if 4 diff. colors are used. since 2 are the same, we make it 4!/2!.and please i need help in question 6 part iv) and v) in nov 10 paper 61 ??
thnx
probability of sth to happen = xi don't understand why sometimes we square or cube our answers? especially in those questions where they asked the probability of something happened for the next three days or next five churches? can someone please explain it for me? thanks
Aoa wr wb!
need help with part b
8 cards are selected with replacement from a standard pack of 52 playing cards, with 12 picture, 20 odd and 20 even cards.
a) how man different arrangememts of 8 cards are possible.
b) how many arrangements in a contain 3 picture, 3 odd and 2 even cards
Answer for first: 5.346 x 10^13
For second: 3.097 x 10^12
ok when can i know exaclty to use the cc, this may lead to losing free easy marks :/usually.
the only situation ive encountered it in is when 'at least' or 'not more than'ok when can i know exaclty to use the cc, this may lead to losing free easy marks :/
they said before in this thread if they said use suitable approximation or random but i understand from ur words that when the random variable X is normally distributed and it is at least or should not be greater we use the cc even if it is normal distribution, right??the only situation ive encountered it in is when 'at least' or 'not more than'
Add (29-45) to -148
CC is only in normal approximation :/they said before in this thread if they said use suitable approximation or random but i understand from ur words that when the random variable X is normally distributed and it is at least or should not be greater we use the cc even if it is normal distribution, right??
uhm, could you explain part b pleasea.
52^8 = 5.346x10^13
b.
12^3/3! * 20^3/3! * 20^2/2! * 8! = 3.097x10^12
you are really a master!!Add (29-45) to -148
add (29-48)^2 to 3089.
and carry on
Since there's replacement so ill not consider P or C. just poweres. since 12 pic cards are there and i have to pic 3. 12^3. dividing by 3! is to cut down the number of arrangements OF THIS SELECTION. same goes for the rest. 8! is an overall arrangement ( 8 cards)uhm, could you explain part b please
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