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AsSalamoAlaikum Wr Wb!even i wanna know..
still im not getting the answer as 0.111..the first value...0.2/174*10^-3=1.149 ms-1.......
where i went wrong?
ms mentions the value of v^2still im not getting the answer as 0.111..the first value...0.2/174*10^-3=1.149 ms-1.......
user
ms mentions the value of v^2
confused...ok wen u squre 1.149 u will get 1.32 v^2...this is the 2nd table in the ms...
oh oh oh got it....
but for the v value i get 1.149 and they rote the range as 0.111 or o.1111....which is the first table....
they didnt mention v value....lol ok
Distance of Card / time
even i wanna know?
Im really Starting to get frustrated from these Uncertaintiesthimzii...i couldnt find how to find that uncertainty?
plot the graph and draw best fit line... then draw worse fit line... take the difference between the best fit line's gradient and worse fit line's gradient... Is that What YOu were trying...??? so something different..???
since distance is constant we just have to find the uncertainty for time only ....
LOL don't worry, I'm pretty much in the same situation as you are. :/omg, you guys make it look soo easy! Man I must suck badly. Sometimes I dont know what can be done to investigate the problem, so I would prolly lose alot in method of data collection...
Man I am really like stuck here, I dont know what Im doing is right. Cz I am looking for all sorts of experiments from Chapter 1... and alot of them I hear for the first time.
This is hopeless, im feeling its really hard to study for the experiments but you guys say that you dont need to. I am soo desperate
me too
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