physics paper 1,2 ........can we discuus da papper nw?

[asd]

i wrote keep the conditions which were used previously same

keep voltage current same and keep wire of differnet lenght and take resistance (that's wrong) ​

pakisatan123, 7 minutes ago ​

 

[pakisatan123]

keep voltage current same and keep wire of differnet lenght and take resistance (that's wrong) ​

pakisatan123, 7 minutes ago ​

ok will i get 1 mark

 

[asd]

ok will i get 1 mark

I hope they be lenient and give you 2 marks. ISA

 

[pakisatan123]

i think one mark each...

what u wrote fr mcq of frequency of wave 2 x 60

 

[pakisatan123]

I hope they be lenient and give you 2 marks. ISA

how many marks u expecting

 

[plantaholic]

1/20 + 1/30 = 3/20 = 1/R
R= 20/3
Total resistance = 20/3 + 10 = 50/3 ohms

the resistance of z was 20 and y 10, so it was 1/10 +1/20= 3/20 i.e. 0.15 total for the parallel. 10 + 0.15= 10.15...

 

[plantaholic]

what u wrote fr mcq of frequency of wave 2 x 60

2 x 60
too

 

[plantaholic]

keep voltage current same and keep wire of differnet lenght and take resistance (that's wrong) ​

pakisatan123, 7 minutes ago ​

we were given a battery so v was constant already

 

[plantaholic]

can anyone please tellwas the total resistance of xyz was? im confused.. help!

 

[plantaholic]

does it matter if we place the ammeter before the wire to be tested in question 8? in series current is same..

 

[ahnime]

i
it was 2p
pressure remain same in all the vessel...... p1*v1=p2*v2
200*p=x*100 solve it we will get the 2p has a result

You get 2p/3, not 2 p.

 

[plantaholic]

i
it was 2p
pressure remain same in all the vessel...... p1*v1=p2*v2
200*p=x*100 solve it we will get the 2p has a result

mine was 2p too... thank God! there's somebody who got the same answer... im feeling like a dumbo

 

[asd]

the resistance of z was 20 and y 10, so it was 1/10 +1/20= 3/20 i.e. 0.15 total for the parallel. 10 + 0.15= 10.15...

You had to divide 1 by 3/20 to get 20/3 . This was for parallel and then add 10.
resistances in parallel = 1/R(1) + 1/R(2) = 1/R
so 3/20 wasn't R, it was 1/R.

 

[muhammadrafay]

i
it was 2p
pressure remain same in all the vessel...... p1*v1=p2*v2
200*p=x*100 solve it we will get the 2p has a result

No it is 200*p=300*p2

 

[muhammadrafay]

and where did we have to point the arrow at the water molecule X in paper 2? That wave question?

I think it was down

 

[plantaholic]

You had to divide 1 by 3/20 to get 20/3 . This was for parallel and then add 10.
resistances in parallel = 1/R(1) + 1/R(2) = 1/R
so 3/20 wasn't R, it was 1/R.

oops!

 

[ahnime]

i
it was 2p
pressure remain same in all the vessel...... p1*v1=p2*v2
200*p=x*100 solve it we will get the 2p has a result

The equation you get is 200*P=300*x because when the tap opened, the new pressure was 300 cm^3. The law is that for an equal mass of gas at constant temperature, p1*v1=p2*v2

 

[plantaholic]

You had to divide 1 by 3/20 to get 20/3 . This was for parallel and then add 10.
resistances in parallel = 1/R(1) + 1/R(2) = 1/R
so 3/20 wasn't R, it was 1/R.

how many marks did it carry? and how many d'you think i'll get?

 

[plantaholic]

The equation you get is 200*P=300*x because when the tap opened, the new pressure was 300 cm^3. The law is that for an equal mass of gas at constant temperature, p1*v1=p2*v2

wasn't the temp constant?

 

[ahnime]

i did it upwards

It was supposed to be a double headed arrow, pointing upwards and downwards. The next one, when you had to mark D should have had 3 crests in it (2 wavelenghts)