AS Physics P1 MCQs Preparation Thread.

[Jaf]

If the total pressure at the top caused the water to move up, water would be sprouting out from the straw even without the child applying any pressure on it. And with greater intensity! - since without the child sucking on the straw the pressure would be even greater at 1.0p₀!

Dude, say what you've written out loud and tell me if it makes sense to you. It doesn't, to me.

The following is my explanation:
So p₀ is the pressure inside the straw including where it is touching the liquid. Now, since the kid is only able to produce a pressure difference of 0.1p₀, we need to find out how much difference this change in pressure will produce in the height of the liquid (inside the straw, ofcourse).
Δp=Δhρg (makes sense?)
This would be, after substituting, 0.1p₀ = Δhρg

We also want this pressure change to be enough for the child be able to drink the liquid (as mentioned in the question). If the length of the straw is longer than the height change (Δh) that the pressure difference can produce, the liquid will obviously not reach the top. This means the length of the straw should be equal to the height change (Δh) in order for the liquid to be drawn to the top. Hence Δh = length of straw. This is why the answer is A.

Kudos!

 

[arlery]

Question 3 and 18 plz with description............

In Q 3 we check the which equation will be homogenous.

 

[1357913579]

Question 3 and 18 plz with description............

3- by seing which equatioon is homogenious A is the answe as ms^-1 on both sides
21- 5+x-10=x-50+y
where i took x as the potential energy at p and y as the kinetic energy at q got y=45 which is the answe
hope you understand if you dont understand do tell me

 

[Oliveme]

Can someone please help me with these question? 11, 14, 29, and 36. thank you.

 

[xxxtoughxxx]

NOV 2003 Q16 how de we know H is greater than T?? thx

 

[Peter Check]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_12.pdf
can sumone look at 37, its on electricity. Why does the pd across the resistor increase? Isnt the workdone per unit charge the same??

 

[Peter Check]

density = mass/volume
density = 50 / 10
density = 5.0

KK thank you so much!

 

[Peter Check]

k
u knw dat 10N is in the centre of the rod
so 10N * 0.50m = Fsin30 * 1m
hence F = 10N.
is the answer C

hey can you answer question 12 in http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf. It also a sum in moments.

 

[Peter Check]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf how do we do question 25??

 

[Peter Check]

CAN ANYONE TELL ME THE RELATIONSHIP BETWEEN WORK DONE AND POTENTIAL DIFFERENCE?? If more wrk is being done across a component(for ex due to increased resistance), does the pd across it increase or decrease? I think it should increase, because pd is the work done per unit charge, so if the work done increases, so would the pd. AM I right?

 

[XPFMember]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf
can sumone look at 37, its on electricity. Why does the pd across the resistor increase? Isnt the workdone per unit charge the same??

When light increases, resistance of LDR 'decreases'. p.d. is proportional to R so p.d also decreases. We know that, in series, pd gets divided..so if the pd across LDR decreases...the pd across resistor will increase [total pd same..]

 

[Peter Check]

When light increases, resistance of LDR 'decreases'. p.d. is proportional to R so p.d also decreases. We know that, in series, pd gets divided..so if the pd across LDR decreases...the pd across resistor will increase [total pd same..]

kk ty

 

[MysteRyGiRl]

The 10s time estimate is a bit of general knowledge if you watch sports.
You could always work backwards by calculating the speed of the sprinter in all 4 choices. In A his speed would be too slow because it's jogging speed. C and D are too fast for any human to run. So B becomes the best estimate of his KE/speed.

oh k thnx

 

[MysteRyGiRl]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Q no 22 plz///am getting 1/4 :?

 

[leosco1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Q no 22 plz///am getting 1/4 :?

(Where E is the Young Modulus, I rearranged the equation to make F the subject and divided the ratios accordingly).

 

[leosco1995]

How do we solve it?

 

[leosco1995]

Can someone please help me with these question? 11, 14, 29, and 36. thank you.

Q11. Relative speed of approach = Relative speed of separation.

The formula for this is:

U1 - U2 = V2 - V1
UA - (-UB) = VB - VA
UA + UB = VB - VA

In fact, you don't even need this formula. Just closely look at the diagram. The relative speed of UA and UB is UA + UB, and the relative speed of VA is VB - VA.

Q14.
Note: The rod weights 100g and is at the middle mark (50 cm).

(60 * 20) + (100 * 10) = 50x
x = 44cm.

Q29. We are looking for the value of 'd'.

d sin θ = nλ
d sin 21.5° = 2 * 590 * 10^-9 (21.5 because we need the angle between the central max and 2nd order, not both 2nd orders)
d = 3.2 μm.

Q36. Find the total current in the circuit, it's 2/(Total Resistance) = 2/7.5 = 0.266A

At X, the voltage is 0.266 * 5 = 1.33V (V=IR)
At Y, the voltage is 0.266 * 10 = 2.66V

The difference between them is 2.66 - 1.33 = 1.33V.

Now see which option is correct.

In A, 2/3 * 2 = 1.33V. Therefore A is right.

 

[fatemakhan]

question number : 27
year : summer 2011
variant : 11
HELP!!!!

 

[fatemakhan]

question number : 28
year : summer 2011
variant : 11
HELP!!!!

 

[fatemakhan]

question number : 31
year : summer 2011
variant : 11
HELP!!!!