AS Physics P1 MCQs Preparation Thread.

[leosco1995]

question number : 28
year : summer 2011
variant : 11
HELP!!!!

If the plates are not parallel, then that means where the 2 plates are closest, they get the strongest field lines right? And the field lines get weaker as the plates become further apart (which is what is happening in options A and D). And the field lines can't be straight if the plates aren't parallel, so the answer should be A.

(Also, it would be helpful if you post an image or link to the question).

For Q27, use the diffraction grating formula to find the angle of the maximum order. That should be 3. So there will be 3 on each side and the central max, which is 7 in total.

 

[leosco1995]

question number : 31
year : summer 2011
variant : 11
HELP!!!!

Q = I * t
Q = 10 * 1 = 10 C

1 ē ....... 1.6 * 10^-19 C
x ē ....... 10 C

= 6.3 * 10^-19 electrons. Also, for the record, the area doesn't matter in this question because Q = I * t. There's no area in this formula and 10A is flowing through the current.

 

[fatemakhan]

If the plates are not parallel, then that means where the 2 plates are closest, they get the strongest field lines right? And the field lines get weaker as the plates become further apart (which is what is happening in options A and D). And the field lines can't be straight if the plates aren't parallel, so the answer should be A.

(Also, it would be helpful if you post an image or link to the question).

For Q27, use the diffraction grating formula to find the angle of the maximum order. That should be 3. So there will be 3 on each side and the central max, which is 7 in total.

for Q27:
d*sintheta=n*lampda
1/500^-3=2 (this is d)
sin90=1
lampda=600*10^-9
put in formula n u get n=3.3*106 !!!

 

[thunderingthunder]

Can anyone please help me with May/June 2008 Q14,Q26 and Q27?

 

[MysteRyGiRl]

(Where E is the Young Modulus, I rearranged the equation to make F the subject and divided the ratios accordingly).

soryy i didnt read da question completelyJA

 

[alibintahir]

Q26. ON/2011/P12

 

[Silent Hunter]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s05_qp_1.pdf

4: why not D why its C ?

and 32,36

 

[MysteRyGiRl]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Q no 27 plzz

 

[MysteRyGiRl]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf

4: why not D why its C ?

and 32,36

im not sure abt Q 4 but i think we take da rounded up value mayb dats y..?
for Q 32, use da formula e=Q/q (q is da electron charge 1.6*10^-19 and Q will be current multiplied by time)
for Q 36 they r asking us which equation is correct and since D is da only equation where both da emfs are subtracted (V-V1) it willl be da answer

 

[smzimran]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf

4: why not D why its C ?

and 32,36

Q4:
The greatest number of significant figures given in question data are :
3 s.f in value
1 s.f in uncertainty


The answer should be 3 s.f in actual value and 1 s.f in uncertainty, thats why....

Q32:
They are not saying about number of electrons per unit cross sectional area, they are asking abt the particular cross sectional area so we will take the current to be 10A.

Q = It and Q = ne
It = ne
n = It / e
n = 10 * 1 / 1.6 * 10^-19
n = 6.25 * 10^19
Answer is C

Q36:
In this question, V2 = V3 because they are in parallel and voltage is same in parallel
and thus V = V1 + V2 or V = V1 + V3

D is correct because from the red marked equation,
V - V1 = V3

 

[smzimran]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Q no 27 plzz

Distance b/w succesive maxima means
(n/2) lambda = 15 mm
n = 1
so
lambda / 2 = 15 mm
lambda = 30 mm = 0.03 m

c = f * lambda
f = c / lambda
f = ( 3 * 10^8 ) / ( 0.03 )
f = 1 * 10^10 Hz

C is the answer

 

[Silent Hunter]

Q32:
They are not saying about number of electrons per unit cross sectional area, they are asking abt the particular cross sectional area so we will take the current to be 10A.

Q = It and Q = ne
It = ne
n = It / e
n = 10 * 1 / 1.6 * 10^-19
n = 6.25 * 10^19
Answer is C

Q36:
In this question, V2 = V3 because they are in parallel and voltage is same in parallel
and thus V = V1 V = V1 + V3 + V2 or

D is correct because from the red marked equation,
V - V1 = V3

thanks alot .. which formula is the light blue one? i dont remember any such formula.... please..

 

[MysteRyGiRl]

Distance b/w succesive maxima means
(n/2) lambda = 15 mm
n = 1
so
lambda / 2 = 15 mm
lambda = 30 mm = 0.03 m

c = f * lambda
f = c / lambda
f = ( 3 * 10^8 ) / ( 0.03 )
f = 1 * 10^10 Hz

C is the answer

aaaah thanxxx JA

 

[smzimran]

thanks alot .. which formula is the light blue one? i dont remember any such formula.... please..

charge is equal to number of electrons * charge on one electron

 

[Silent Hunter]

charge is equal to number of electrons * charge on one electron

oh i see . silly me ... JazakAllah bro

 

[smzimran]

oh i see . silly me ... JazakAllah bro

Wa iyyakum

 

[MysteRyGiRl]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
umm Q no 29 and 33 plzz

 

[Saad Rauf]

Now this is something that I was crazy about studying! Thank you so much for whoever created the thread and those helping with the questions and answers! God bless ya!

 

[Knight]

3- by seing which equatioon is homogenious A is the answe as ms^-1 on both sides
21- 5+x-10=x-50+y
where i took x as the potential energy at p and y as the kinetic energy at q got y=45 which is the answe
hope you understand if you dont understand do tell me

how did you make the equation in Q18????

 

[mahnoor shah]

oct/nov 2011 mcq 11 and 14
plzzz help