AS Physics P1 MCQs Preparation Thread.

[A.ELWY 7]

by the way if we are going to choose 4 ppl from here to help in the explanation of the exams i back SMZIMRAN to be one of the 4 ppl

 

[MOMO123123]

its on the website, in the examiners report

 

[USMAN Sheikh]

ANYONE PLS QUES 10 and 20 ??? with detail explanation pls

 

[geek101]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf

Q5, 7 , 10 , 18, 26

7 - if you resolve the vector you will see that the horizontal component is ucosα while there are two vertical components...taking in mind that they are acting in the opposite directions. First is the result of resolving the vector on the y axis : usinα and the second is the acceleration downwards. But you cant subtract these so you will take the acceleration in terms of the velocity:
since (a = (v-u) / t) therefore, delta v = at replace the a with g becuz they have the same value therefore the vertical component downwards is gt.
so the vertical component is usinα - gt .....the answer is C

10 - i dunno if this is the right way but this is how i did it....since x = m and y = 3m. Take the force as 1 F if you divide the force according to their mass....so x gets 1/4 F and Y gets 3/4F hence the force exerted on y by x is 3/4 F. so D

18 - use V2 = U2 + 2as
for the first case:
v= 0, u= 10 and s=10
so putting it into the equation:
0 = 100 + 2(10)(a)
a= -5
now the second case:
v = 0, u=30 a=-5 (since the force is the same)
so 0 = 900 - 10s
s = 90 m
and the answer is D

26 - the time period (T) is the time taken for one wave, which is 2.5 x 10^-3 x 4 = 0.01
F = 1/T
= 1/0.01 = 100 Hz so the answer is B

gimme sometime till i figure out 5
this is what the examiner report says about 5:
A and B were common responses. Perhaps candidates did not see the significance of the fact that 3% of 330 is 10 but just tried to give rounding to 3 or 4 significant figures.

 

[smzimran]

that would be good too but the problem is we will have to make group of 3-4 people or else server gets bussy i reckon we can do that for doubts which are really difficult hard to capture from here

We tried for 6 six people the server was ok, but i dont know beyond that!
But their must be a good anchor person, otherwise the discussion is useless, it turns into a fish market!

 

[smzimran]

Aoa wr wb!
But that's not always possible..

*privacy issues*

A new account can be made revealing none of your information, except the voice, and i dont think voice is a problem, right ?

 

[1357913579]

We tried for 6 six people the server was ok, but i dont know beyond that!
But their must be a good anchor person, otherwise the discussion is useless, it turns into a fish market!

if you remember all the concepts so i suppose youll be enough to help as i dont think anyone will get more than 3-4 doubts per paper,
the problem will be there will be people here who will from different countries and which creates the problem with server so i reckon it will be a problem.

 

[smzimran]

if you remember all the concepts so i suppose youll be enough to help as i dont think anyone will get more than 3-4 doubts per paper,
the problem will be there will be people here who will from different countries and which creates the problem with server so i reckon it will be a problem.

I'll be glad to, but the thing is i wont be online for too long each day, nor can i promise to be consistently online, but if iam online i will try my best to help!

 

[kinglynx]

 

[kinglynx]

can anyone explain those questions above? (i forgot to say that haha)

 

[smzimran]

can anyone explain those questions above? (i forgot to say that haha)

My neck would get out of place!

 

[iKhaled]

does anyone has the 2002 mark scheme?

 

[umarashraf]

does anyone has the 2002 mark scheme?

 

[good man12]

can anyone explain those questions above? (i forgot to say that haha)

sure. in the last one about wire.................you knoe that resistence is directly proportional to length and inversely proportional to CSA, hence, since the lenth is same, but you have N number of wires, each has area of AREA/N..hence resistance of individual wores increases, but since there are N wires in paralel when we apply 1/R1 1/R2 + 1/Rn ..............it sums up to be N/RN....the N cancels and take inverse, so resistence is R.....equal

 

[umarashraf]

sure. in the last one about wire.................you knoe that resistence is directly proportional to length and inversely proportional to CSA, hence, since the lenth is same, but you have N number of wires, each has area of AREA/N..hence resistance of individual wores increases, but since there are N wires in paralel when we apply 1/R1 1/R2 + 1/Rn ..............it sums up to be N/RN....the N cancels and take inverse, so resistence is R.....equal

and hows your neck now..????

 

[A.ELWY 7]

Seriously guys...im feeling that there is no serious consideration about starting with the revision from 2003, if there will be nothing then lets leave any person post his doubts and the others answer!!!

 

[umarashraf]

Seriously guys...im feeling that there is no serious consideration about starting with the revision from 2003, if there will be nothing then lets leave any person post his doubts and the others answer!!!

Dear Cristiano Ronaldo... its a good idea... infact so many days are left that there is no need to study even..

 

[xxxtoughxxx]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w03_qp_1.pdf........ Q16 i duno how 2 do this thing helpp ppl ??

 

[geek101]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w03_qp_1.pdf........ Q16 i duno how 2 do this thing helpp ppl ??

well i dunno but i did it in quite an easy way.....you know that when 3 forces are acting their lines of action must pass through the same point. If you extend them all till they meet, and compare the size you will se W is the smallest magnitude then H and then T. so the answer is C

 

[hendrixgirl]

may june 2003 .. question 3?