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No it was 6 point something...Was your acceleration -1.7?
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No it was 6 point something...Was your acceleration -1.7?
http://www.xtremepapers.com/community/threads/as-physics-p1-mcqs-yearly-only.17330/Yes please! Its getting too confusing this way. :/
How about we make a separate thread for the random MCQ doubts and leave this one for the year by year solving..?
http://www.xtremepapers.com/community/threads/as-physics-p1-mcqs-yearly-only.17330/that would be good too but the problem is we will have to make group of 3-4 people or else server gets bussy i reckon we can do that for doubts which are really difficult hard to capture from here
Its quite simple:Question no 8 pls i have gone for C but its A why ????
no one is reply me pls the above ques and q31 and 33 of this year pls waiting for help pls matesQuestion no 8 pls i have gone for C but its A why ????
thanks alot mate can u pls ans my other questions tooIts quite simple:
When an object falls under gravity for quite sometime, it eventually gains constant 'terminal velocity'. That means 'g' drops to zero or almost zero in order for speed to be constant!
C is wrong as it shows no indication of g reducing to zero and terminal velocity being reached.
A is correct!
How do we do this? What I did was to find the resultant force down the slope(taking the friction force into account) then use that force to find the acceleration, and then use the formula v^2= 2as where s is 7m. I got 9.5m/s, which is not even in the options!!View attachment 11874
Q16:
Q16:
input energy = F.s
output energy = mgh = mg (s sin@) = mgs sin@
efficiency = output / input
= mgs sin@ / Fs
= mg sin@ / F
So, D is correct
Q24: wave properties (check the text book)
Q31:no one is reply me pls the above ques and q31 and 33 of this year pls waiting for help pls mates
No, always remember in these cases, output is the workdone in lifting the load through a height hnae bhae input shuld be mgh or 1/2 m v^2 and output shuld be F*s...i thnk...?
welcome...any timereally impressed by the explanation to Q27...i was trying so hard since O level to figure out some imagination of this sort for these questions...thnx n best of luck
oooohhh u just couldn't imagine how was this question a torture for me...but i finally solved it, see:How do we do this? What I did was to find the resultant force down the slope(taking the friction force into account) then use that force to find the acceleration, and then use the formula v^2= 2as where s is 7m. I got 9.5m/s, which is not even in the options!!View attachment 11874
can someone please explain to me question 19
isn't work done in a gas = p * V ?
so there is loss of energy overall[/quot if u have mark scheme of this paper do post it...PLEASE..
cant iD???Q31:
Q33:
The formula is
V = I (R + r)
C is the answer!
can someone please explain to me question 19
isn't work done in a gas = p * V ?
so there is loss of energy overall
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