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by the way if we are going to choose 4 ppl from here to help in the explanation of the exams i back SMZIMRAN to be one of the 4 ppl
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We tried for 6 six people the server was ok, but i dont know beyond that!that would be good too but the problem is we will have to make group of 3-4 people or else server gets bussy i reckon we can do that for doubts which are really difficult hard to capture from here
A new account can be made revealing none of your information, except the voice, and i dont think voice is a problem, right ?Aoa wr wb!
But that's not always possible..
*privacy issues*
if you remember all the concepts so i suppose youll be enough to help as i dont think anyone will get more than 3-4 doubts per paper,We tried for 6 six people the server was ok, but i dont know beyond that!
But their must be a good anchor person, otherwise the discussion is useless, it turns into a fish market!
I'll be glad to, but the thing is i wont be online for too long each day, nor can i promise to be consistently online, but if iam online i will try my best to help!if you remember all the concepts so i suppose youll be enough to help as i dont think anyone will get more than 3-4 doubts per paper,
the problem will be there will be people here who will from different countries and which creates the problem with server so i reckon it will be a problem.
My neck would get out of place!can anyone explain those questions above? (i forgot to say that haha)
does anyone has the 2002 mark scheme?
sure. in the last one about wire.................you knoe that resistence is directly proportional to length and inversely proportional to CSA, hence, since the lenth is same, but you have N number of wires, each has area of AREA/N..hence resistance of individual wores increases, but since there are N wires in paralel when we apply 1/R1 1/R2 + 1/Rn ..............it sums up to be N/RN....the N cancels and take inverse, so resistence is R.....equalcan anyone explain those questions above? (i forgot to say that haha)
sure. in the last one about wire.................you knoe that resistence is directly proportional to length and inversely proportional to CSA, hence, since the lenth is same, but you have N number of wires, each has area of AREA/N..hence resistance of individual wores increases, but since there are N wires in paralel when we apply 1/R1 1/R2 + 1/Rn ..............it sums up to be N/RN....the N cancels and take inverse, so resistence is R.....equal
Seriously guys...im feeling that there is no serious consideration about starting with the revision from 2003, if there will be nothing then lets leave any person post his doubts and the others answer!!!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w03_qp_1.pdf........ Q16 i duno how 2 do this thing helpp ppl ??
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