AS Physics P1 MCQs Preparation Thread.

[Knight]

may i know what year is this...i got A as an answer is that right??

june 11 paper-12 and the answer is C

 

[DARK DRAGON]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_12.pdf
Q 19 answer is D explain plz

 

[Henry930821]

Hey guys, can anyone explain to me in detailed steps how to do question 7 of O/N/05 please? Thanks! Sorry having trouble in posting question

 

[Knight]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf
Q 19 answer is D explain plz

energy is equla to work done.......
W=F/s
=10/(5*10^-3)
=2000 N ( D )

 

[leosco1995]

Hey guys, can anyone explain to me in detailed steps how to do question 7 of O/N/05 please? Thanks! Sorry having trouble in posting question

For distance x from rest,

s = ut + 0.5at^2
x = 0.5a * t1^2

For distance h from rest,

h + x = 0.5a * t2^2

Place x from equation 1 into equation 2,

h + 0.5a * t1^2 = 0.5 * a * t2^2
0.5a(t1-t2)^2 = h
a = 2h/(t1-t2)^2

 

[leosco1995]

http://www.freeexampapers.com/get_p... Level/Physics/CIE/2002 Jun/9702_s02_qp_1.pdf

plz helpp

I posted the solutions of all June 2002 questions in the other thread.
http://www.xtremepapers.com/community/posts/317510

Kind of rushed it so some answers might not be clear, but it should help anyway.

 

[A.ELWY 7]

june 11 paper-12 and the answer is C

ok i know may mistake now..i was confused between A and C, but pls post the question again cause i lost it

 

[freakybandi]

Using equation - m1*u1 + m2*u2 = m1*v1 + m2*v2 where m1 = 20 kg, m2 = 12 kg, u1 = 6m/s, u2 = -15 m/s as it's traveling in the OPPOSITE direction. You MUST NOT ignore directions! so the equation becomes m1u1 + m2u2 = v*(m1 + m2) as they now stick together and have the same final velocity.
(20*6) + (12*-15) =v*(20+12) -------> -60 = -32v as they are traveling towards the bigger speed (-15) and we have taken this direction as negative (-).
answer is v = -60/-32 = 1.875 rounding off 1.9 m/s. answer is A.

ohh thank you so much!!!!

 

[thunderingthunder]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Can anyone please help me with Q.25?Shouldn't the answer be C?
Also please I need help in Q.26!
Thank you in advance

 

[Iadmireblue]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s04_qp_1.pdf

question 25 and question 38

 

[xxfarhaxx]

posting ths fr da 2nd tym ppl!! pls do hlp!!
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_1.pdf
http://www.xtremepapers.com/papers/...el/Physics (9702)/9702_s03_ms_1+2+3+4+5+6.pdf
Q- 3, 11 ,18, 20, 22, 30,35, 40

 

[Iadmireblue]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Can anyone please help me with Q.25?Shouldn't the answer be C?
Also please I need help in Q.26!
Thank you in advance

for question 26,you can see from the picture that 210 cm is equal to 1.5 wavelength's.
Therefore 1 wavelenght is equal to 2.1 meters/1.5 lambda and you get 1.4
speed = frequency x wavelength speed = 80 x 1.4 =112m/s

 

[raamish]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf

qs 22) I did this: total force applied*total extension=550*12. What mistake did i make.

 

[thunderingthunder]

for question 26,you can see from the picture that 210 cm is equal to 1.5 wavelength's.
Therefore 1 wavelenght is equal to 2.1 meters/1.5 lambda and you get 1.4
speed = frequency x wavelength speed = 80 x 1.4 =112m/s

thank you and Q 25 please!!

 

[Iadmireblue]

posting ths fr da 2nd tym ppl!! pls do hlp!!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf
Q- 3, 11 ,18, 20, 22, 30,35, 40

q3-I'm not 100% sure about this one but if you draw a horizontal line you can draw a right angle triangle and you will see thatthe hypotenuse or resultant is equal to 10N
q11-The answer is B,i have no idea why :/
q18-If any object is travveling with twice the speed it will take 4 times the distance for the object to come to a halt --->Recall the equation v2=u2+2as
so if the object is travelling with 3x speed it will take 9x the distance for it to come to rest,the answer is D

 

[Iadmireblue]

thank you and Q 25 please!!

I did 25 and even i got c :/

 

[xxfarhaxx]

q3-I'm not 100% sure about this one but if you draw a horizontal line you can draw a right angle triangle and you will see thatthe hypotenuse or resultant is equal to 10N
q11-The answer is B,i have no idea why :/
q18-If any object is travveling with twice the speed it will take 4 times the distance for the object to come to a halt --->Recall the equation v2=u2+2as
so if the object is travelling with 3x speed it will take 9x the distance for it to come to rest,the answer is D

thnx n wt abt da rst,,no idea???

 

[Henry930821]

For distance x from rest,

s = ut + 0.5at^2
x = 0.5a * t1^2

For distance h from rest,

h + x = 0.5a * t2^2

Place x from equation 1 into equation 2,

h + 0.5a * t1^2 = 0.5 * a * t2^2
0.5a(t1-t2)^2 = h
a = 2h/(t1-t2)^2

Thanks a million!!

 

[leosco1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf

qs 22) I did this: total force applied*total extension=550*12. What mistake did i make.

You are supposed to find the area of the region from 0 to X individually and X to Y individually. That's 2.5 + 1.05 = 3.55 J.

 

[Oliveme]

ohh thank you so much!!!!

you're welcome