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AS Physics P1 MCQs Preparation Thread.

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Henry930821

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Hey guys, can anyone explain to me in detailed steps how to do question 7 of O/N/05 please? Thanks! Sorry having trouble in posting question
 
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leosco1995

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Henry930821 said:
Hey guys, can anyone explain to me in detailed steps how to do question 7 of O/N/05 please? Thanks! Sorry having trouble in posting question
Click to expand...
For distance x from rest,

s = ut + 0.5at^2
x = 0.5a * t1^2

For distance h from rest,

h + x = 0.5a * t2^2

Place x from equation 1 into equation 2,

h + 0.5a * t1^2 = 0.5 * a * t2^2
0.5a(t1-t2)^2 = h
a = 2h/(t1-t2)^2
 
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freakybandi

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Oliveme said:
Using equation - m1*u1 + m2*u2 = m1*v1 + m2*v2 where m1 = 20 kg, m2 = 12 kg, u1 = 6m/s, u2 = -15 m/s as it's traveling in the OPPOSITE direction. You MUST NOT ignore directions! so the equation becomes m1u1 + m2u2 = v*(m1 + m2) as they now stick together and have the same final velocity.
(20*6) + (12*-15) =v*(20+12) -------> -60 = -32v as they are traveling towards the bigger speed (-15) and we have taken this direction as negative (-).
answer is v = -60/-32 = 1.875 rounding off 1.9 m/s. answer is A.
Click to expand...
ohh thank you so much!!!!
 
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Iadmireblue

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Iadmireblue

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xxfarhaxx said:
posting ths fr da 2nd tym ppl!!:( pls do hlp!!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_ms_1 2 3 4 5 6.pdf
Q- 3, 11 ,18, 20, 22, 30,35, 40
Click to expand...
q3-I'm not 100% sure about this one but if you draw a horizontal line you can draw a right angle triangle and you will see thatthe hypotenuse or resultant is equal to 10N
q11-The answer is B,i have no idea why :/
q18-If any object is travveling with twice the speed it will take 4 times the distance for the object to come to a halt --->Recall the equation v2=u2+2as
so if the object is travelling with 3x speed it will take 9x the distance for it to come to rest,the answer is D
 
xxfarhaxx

xxfarhaxx

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Iadmireblue said:
q3-I'm not 100% sure about this one but if you draw a horizontal line you can draw a right angle triangle and you will see thatthe hypotenuse or resultant is equal to 10N
q11-The answer is B,i have no idea why :/
q18-If any object is travveling with twice the speed it will take 4 times the distance for the object to come to a halt --->Recall the equation v2=u2+2as
so if the object is travelling with 3x speed it will take 9x the distance for it to come to rest,the answer is D
Click to expand...
thnx n wt abt da rst,,no idea???
 
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Henry930821

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leosco1995 said:
For distance x from rest,

s = ut + 0.5at^2
x = 0.5a * t1^2

For distance h from rest,

h + x = 0.5a * t2^2

Place x from equation 1 into equation 2,

h + 0.5a * t1^2 = 0.5 * a * t2^2
0.5a(t1-t2)^2 = h
a = 2h/(t1-t2)^2
Click to expand...
Thanks a million!!
 
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