Physics paper 1 AS level doubts here!!!

applepie1996

applepie1996

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anonymous123 said:
9702 s11 qp 11
Q9
thx
Click to expand...
momentum b4 collision=momentum after collision
so...... mass of body 1=m
mass of body 2=m
speed of body 1 =v
speed of body 2=0
m x v + m x 0 = 2m x s s is the new speed which we find to find momentum after collision
mv = 2ms
so s=v/m
so momentum after collision = 2m x s where s = v/m
so momentum after collision = 2m x v/m m gets cancelled which leaves with mv
i'll do the ke part and tell u later
 
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anonymous123

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applepie1996 said:
momentum b4 collision=momentum after collision
so...... mass of body 1=m
mass of body 2=m
speed of body 1 =v
speed of body 2=0
m x v + m x 0 = 2m x s s is the new speed which we find to find momentum after collision
mv = 2ms
so s=v/m
so momentum after collision = 2m x s where s = v/m
so momentum after collision = 2m x v/m m gets cancelled which leaves with mv
i'll do the ke part and tell u later
Click to expand...
You don't need to do that calculation. initial momentum = mv because one body is stationary so final is also = mv. im confused about the ke part since ke is not conserved.
 
applepie1996

applepie1996

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anonymous123 said:
You don't need to do that calculation. initial momentum = mv because one body is stationary so final is also = mv. im confused about the ke part since ke is not conserved.
Click to expand...
i think K.E is halved because the 2 bodies are of the same masses so the ke splits??
 
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Sana101

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I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)


O/N 2002 Q14) Answer is C
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w02_qp_1.pdf

M/J 2004 Q14) Answer is 9 and Q16) Answer is 6
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s04_qp_1.pdf

M/J 2005 Q14) AND Q)13 AND Q)16
www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s05_qp_1.pdf

M/J 2006 Q25) Answer is A
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf

OCT/NOV 2006 Q15) Answer is C
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w06_qp_1.pdf

OCT/NOV 2007 Q25) Answer is B
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf

OCT/NOV 2008 Q4) Answer is D
www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w08_qp_1.pdf​
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
O/N 2002 Q14)
0=50 * x + 100 * 10 - 20 * 60
so x=4 cm away from pivot which is at 40 cm so mark at 44cm
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
i think u got the m/j 04 part wrong
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
question 14 i'll do and tell
Q13) IS 20 x 3 - 5 x 2 - 10 x 2 =30Nm
negative because they move in opposite direction and it is 10N MULTIPLY BY 2m BECAUSE IT MOVES THROUGH A HEIGHT OF 2m
Q16)IT IS THE INSTANT BETWEEN 2 - 3 SECONDS SO A TRIANGLE IS FORMED WHICH 0.5 X 1 X HEIGHT WHICH IS 30 J SO ANSWER IS 30
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
mj/05 Q25
you first find lambda using frequency and speed so it is 340/500=0.68m
a wavelength=2pie sooo 0.68 is 2pie then 0.17 = 0.17 x 2pie/0.68 = pie/2
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
OCT/NOV 2006 Q15)
u find the vertical component which is 10 cos 30 x 2 (x2 because both the sides are exerted by equal forces)=17.3N
subtract this answer from 10 to find the resultant force=7.3N
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
OCT/NOV 2007 Q25)
d sin theta = n L (L = wavelength)

sin 45 = n x (L/d) = 3 L/d = 0.707. So L/d = .7/3 = 0.23

Since sin theta cannot be greater than 1, n cannot be greater than 1/0.23, which is 4.2...

So the greatest order is 4.
 
applepie1996

applepie1996

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Sana101 said:
I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)​
​
​
O/N 2002 Q14) Answer is C​
M/J 2004 Q14) Answer is 9 and Q16) Answer is 6​
M/J 2005 Q14) AND Q)13 AND Q)16​
M/J 2006 Q25) Answer is A​
OCT/NOV 2006 Q15) Answer is C​
OCT/NOV 2007 Q25) Answer is B​
OCT/NOV 2008 Q4) Answer is D​
Click to expand...
the percentage uncertainty is 1% so uncertainty is 1/100=0.01
so x/1.98=0.01 so x=0.02
x/2.02=0.01 so x=0.02
total uncertainty is 0.02+0.02 =0.04
 
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robotic94

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Beaconite007 said:
Q.5 and Q.24
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
Click to expand...
5. B
Frequency: 3000 oscillations in a min, ie, 3000/60sec= 50
now Time period= 1/50= 0.02
and so for time base, as this is for one full wave, divide it by 2, 0.02/2= 0.01
24. C
peak position, particles at rest.
particles leading crest move up.
Hey help me as well.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
q 7,9, 10, 18, 22
 
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