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I'll try and clear as many as i can
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ok i will check it out now9702 s11 qp 11
Q9
thx
momentum b4 collision=momentum after collision9702 s11 qp 11
Q9
thx
You don't need to do that calculation. initial momentum = mv because one body is stationary so final is also = mv. im confused about the ke part since ke is not conserved.momentum b4 collision=momentum after collision
so...... mass of body 1=m
mass of body 2=m
speed of body 1 =v
speed of body 2=0
m x v + m x 0 = 2m x s s is the new speed which we find to find momentum after collision
mv = 2ms
so s=v/m
so momentum after collision = 2m x s where s = v/m
so momentum after collision = 2m x v/m m gets cancelled which leaves with mv
i'll do the ke part and tell u later
i think K.E is halved because the 2 bodies are of the same masses so the ke splits??You don't need to do that calculation. initial momentum = mv because one body is stationary so final is also = mv. im confused about the ke part since ke is not conserved.
O/N 2002 Q14)I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
i think u got the m/j 04 part wrongI need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
question 14 i'll do and tellI need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
mj/05 Q25I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
OCT/NOV 2006 Q15)I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
OCT/NOV 2007 Q25)I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
the percentage uncertainty is 1% so uncertainty is 1/100=0.01I need help with the following questions. If someone could please solve even some of them i would be really grateful! =)O/N 2002 Q14) Answer is CM/J 2004 Q14) Answer is 9 and Q16) Answer is 6M/J 2005 Q14) AND Q)13 AND Q)16M/J 2006 Q25) Answer is AOCT/NOV 2006 Q15) Answer is COCT/NOV 2007 Q25) Answer is BOCT/NOV 2008 Q4) Answer is D
5. B
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