AS Physics P1 MCQs Preparation Thread.

[JD REBORN]

That was very helpful, thank you so much! I have a question, though - For Q.26, why did you do 2n+1? Is that something I'm supposed to know?

YESS very important formula!

 

[bloody_mary]

IVE POSTED THE SAME SHIT, ABOUT 5 TIMES NOW AND YOU WONT ANSWER, SO DONT TELL ME TO ASK NICELY OR SAY THIS OR THAT, CAUSE IT OBVIOUSLY DONT WORK

maybe because you don't have a catchy signature nor avatar

and so what i posted my questions 5 times before Sana101 answered them

 

[MysteRyGiRl]

IVE POSTED THE SAME SHIT, ABOUT 5 TIMES NOW AND YOU WONT ANSWER, SO DONT TELL ME TO ASK NICELY OR SAY THIS OR THAT, CAUSE IT OBVIOUSLY DONT WORK

so u think its gona w0rk dis way? post it again...we will help u

 

[Soldier313]

Because you are not getting a simple point.

would you care to elaborate what you explained before?

 

[bloody_mary]

would you care to elaborate what you explained before?

did you get it yet ☻

 

[Nibz]

lol i think Nibz edited it coz first he had written Q downwards.......whatever the case i still don't get it.....did u? If yes pleeasee do help

I edited it because it was a typing mistake. Don't show me your tongue.
Writing Q instead of P doesn't make any difference as long as the explanation is right.

 

[Nibz]

would you care to elaborate what you explained before?

There is nothing to elaborate, dear.
From trough to crest, particles are in downward motion; From crest to trough, they are in upward motion.
At max point, they are momentarily at rest.

 

[Soldier313]

I edited it because it was a typing mistake. Don't show me your tongue.
Writing Q instead of P doesn't make any difference as long as the explanation is right.

lol chill there was no offense meant

 

[Nibz]

IVE POSTED THE SAME SHIT, ABOUT 5 TIMES NOW AND YOU WONT ANSWER, SO DONT TELL ME TO ASK NICELY OR SAY THIS OR THAT, CAUSE IT OBVIOUSLY DONT WORK

You don't pay us, mister. We will only help you if we want; you can't force us.
Don't use your Caps Lock, again.

 

[Soldier313]

did you get it yet ☻

for some reason the second link does not work and the first one didnt solve my pro Oh God!

 

[Soldier313]

There is nothing to elaborate, dear.
From trough to crest, particles are in downward motion; From crest to trough, they are in upward motion.
At max point, they are momentarily at rest.

hmmmm starting to make sense thanx

 

[bloody_mary]

for some reason the second link does not work and the first one didnt solve my pro Oh God!

ok see this vid

just ignore the circle thingy cuz that is higher level
but just look at the overall up and down motion

 

[JD REBORN]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_12.pdf
Q.4, 15, 27, 28, 34 please?

Since all questions have been explained apart from 15 so
For q15 Efficency=Useful Output energy/Input Energy multiplied by 100
Now Input energy=Force*Distance=Fs
For output energy if u read the question carefully the car is moving with constant speed v so it is not gaining kinetic energy.It is only gaining Potential energy.Now u have to calculate height.Whenever u need to calculate h and distance of slope and angle of slope with horizontal is given,use the formula
sin alpha=h/s so h=s sin alpha
Gain in P.E=m*g*s sinalpha
m*g*s sinalpha divided by Fs giving u D as answer

 

[Soldier313]

ok see this vid

just ignore the circle thingy cuz that is higher level
but just look at the overall up and down motion

thhhaaat actually helped! thank you soo soo much! God bless u sis!

 

[Oliveme]

Asalam-o-Alaikum. Please help me with these questions -------> 9, 13, 14, 27 and 29.
for 27, why don't we multiply charge (1.6 x 10^-19) by 2 as there are two protons.

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w09_qp_11.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w09_ms_11.pdf
Thank you very much. May Allah bless you.

 

[samwickz]

hay can any1 help me with this pretty plz i kinda suck @ physics

A motorist travelling at 10ms–1 can bring his car to rest in a braking distance of 10m. In what distance could he bring the car to rest from a speed of 30 m s–1 using the same braking force?
A 17m B 30m C 52m D 90m

the marking scheme ans is D
so any 1 goody good out there mynd helping me out plzzzzzzzzzzzzzz

 

[kinglynx]

Okay, here it is again :
Questions: 10, 11 , 21, 24, 26, 27, 31, 33 ,36

PLEASE HELP URGENTLY!!!! AND EXPLAIN AS WELL, I CAN GET THE ANSWERS FROM A MARK SCHEME I NEED EXPLANATIONS!! THANK YOU GOD BLESS

And i uploaded the question paper too.

 

[xyz!]

thhhaaat actually helped! thank you soo soo much! God bless u sis!

for which question was that video posted...can sum1 post it for me pls?

 

[Nibz]

Okay, here it is again :
Questions: 10, 11 , 21, 24, 26, 27, 31, 33 ,36

PLEASE HELP URGENTLY!!!! AND EXPLAIN AS WELL, I CAN GET THE ANSWERS FROM A MARK SCHEME I NEED EXPLANATIONS!! THANK YOU GOD BLESS

And i uploaded the question paper too.

Q10.

mu1 - mu2 = (m+m)v
60m - 40m = 2mv
20m/2m = v
10 = v


Q11.
Net force = m x a
10 - 4 = 2a
6/2 = a
3 = a

Q24.
f = v/lambda => wavelength and frequency have an inverse proportionality. Increasing f would decrease the wavelength.
With shorter wavelength, diffraction is less pronounced, i.e more closer to diagram 2.

Q31.
R = ρL/A
R . A /L = ρ
Ω m^2 /m = ρ
Ω m = ρ

 

[leosco1995]

culd sum one solve this the answer is C

Since it is a cube, one side is V^1/3

Area is V^2/3

So resistance is ρL/A = (ρ * V^1/3) / V^2/3

= ρ / V^1/3 I think..