AS Physics P1 MCQs Preparation Thread.

[geek101]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf Q5 someone puhllleeeeezz

 

[Soldier313]

copper and diamond are crystalline substances

thanx......so glass is.....?

 

[Capricedcapri]

anyone knows how to solve mcq 5 and 9 of 0ct nov 2010 variant 11??

 

[Capricedcapri]

thanx......so glass is.....?

yes the ans is glass

 

[Soldier313]

yes the ans is glass

so copper and diamond and glass are crystalline?????? sorry i didnt get it

 

[1357913579]

please explain question no 17 and 24 please
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf
ans 17-C
24-B

ASSALAMOALIKUM,
take vertical components of both tention s tentions vertical components would be in opposite direction to p so 4cos53.13 is equal to p note we dont have to multiply by 2 although there are 2 tentions but in question they mentioned tention in eleastic so thats the total tention of the system and i got angle by normal trig
hope that helps

 

[1357913579]

anyone knows how to solve mcq 5 and 9 of 0ct nov 2010 variant 11??

number-5 as 300 revolution per minute means 50 revolution per second so thats the frequesncy time period=1/50 equal to 0.02 seconds and then answer would be 10 becuse 10^-3 multiplied by is 10 equal to 0.01 so hlf wave would be displayed which is clear displayed compared to all other like in option A alot of waves will be produce which will be very hard to see in option c and d very huge wave would be seen making hardly any wavelenght so b is the answer
9-v^2=u^+2as
0^2=u^2+2a(x)
-u^2=2a(x)
a=-u^2/2x -----(1)
v^2=(1.2u)^2+2as
put a=---1
0^2=(1.44u^2)+2(-u^2/2x)(s)
-1.44u^2=-u^2/x (s)
(s)=1.44x
hope that helps

 

[Soldier313]

geek101 Capricedcapri
qn 5 on/11, v 1:
3000 revolutions per minute = 50 revolutions per second, which is basically the frequency
so 50 Hz u use this to find periodic time since T = 1/f
u get 20ms as periodic time -----> 0.02s
then i am not sure if this is the appropriate way of doing it but i used each of the choices and tested like this:
A. ) 1s = 1cm
0.02s = ? u get 0.02 cm so basically each wave occupies just 0.02 cm that's a very high freq and waveforms wont be clear
B. ) 10 ms = 1cm
20ms = ? 2cm , that means each wave will occupy 2 cm, so i will have 5 waveforms, pretty clear
C. ) 100 microsecond = 1cm
20 x 10^ 3 microsecond = ? u get 200cm , whoa! that's impossible , i only have 10 cm on the screen
D .) 1 microsecond = 1cm
20 x 10 ^3 microsecond = ? u get 20 x 10 ^ 3 cm, impossible
hence answer is B

 

[geek101]

geek101 Capricedcapri
qn 5 on/11, v 1:
3000 revolutions per minute = 50 revolutions per second, which is basically the frequency
so 50 Hz u use this to find periodic time since T = 1/f
u get 20ms as periodic time -----> 0.02s
then i am not sure if this is the appropriate way of doing it but i used each of the choices and tested like this:
A. ) 1s = 1cm
0.02s = ? u get 0.02 cm so basically each wave occupies just 0.02 cm that's a very high freq and waveforms wont be clear
B. ) 10 ms = 1cm
20ms = ? 2cm , that means each wave will occupy 2 cm, so i will have 5 waveforms, pretty clear
C. ) 100 microsecond = 1cm
20 x 10^ 3 microsecond = ? u get 200cm , whoa! that's impossible , i only have 10 cm on the screen
D .) 1 microsecond = 1cm
20 x 10 ^3 microsecond = ? u get 20 x 10 ^ 3 cm, impossible
hence answer is B

brilliant sistaa! THANK YOUU good luck for tomorrow, inshaAllah ur gonna come out with a smile on yar face, and ace it!

 

[Soldier313]

ASSALAMOALIKUM,
take vertical components of both tention s tentions vertical components would be in opposite direction to p so 4cos53.13 is equal to p note we dont have to multiply by 2 although there are 2 tentions but in question they mentioned tention in eleastic so thats the total tention of the system and i got angle by normal trig
hope that helps

sorry bt cud u show hw u gt 53.1 as ur angle, coz i gt 45 as my angle.....thanx

 

[Soldier313]

brilliant sistaa! THANK YOUU good luck for tomorrow, inshaAllah ur gonna come out with a smile on yar face, and ace it!

anytym g' luck to you too inshaAllah i hope this du'a is fulfilled and i come out with a smile

 

[Soldier313]

ASSALAMOALIKUM,
take vertical components of both tention s tentions vertical components would be in opposite direction to p so 4cos53.13 is equal to p note we dont have to multiply by 2 although there are 2 tentions but in question they mentioned tention in eleastic so thats the total tention of the system and i got angle by normal trig
hope that helps

sorry bt cud u show hw u gt 53.1 as ur angle, coz i gt 45 as my angle.....thanx

please can u helpp??

 

[1357913579]

please can u helpp??

soory for late replying i was searching for that paper
ok its simple tan theta = 40/30 get theta

 

[1357913579]

geek101 Capricedcapri
qn 5 on/11, v 1:
3000 revolutions per minute = 50 revolutions per second, which is basically the frequency
so 50 Hz u use this to find periodic time since T = 1/f
u get 20ms as periodic time -----> 0.02s
then i am not sure if this is the appropriate way of doing it but i used each of the choices and tested like this:
A. ) 1s = 1cm
0.02s = ? u get 0.02 cm so basically each wave occupies just 0.02 cm that's a very high freq and waveforms wont be clear
B. ) 10 ms = 1cm
20ms = ? 2cm , that means each wave will occupy 2 cm, so i will have 5 waveforms, pretty clear
C. ) 100 microsecond = 1cm
20 x 10^ 3 microsecond = ? u get 200cm , whoa! that's impossible , i only have 10 cm on the screen
D .) 1 microsecond = 1cm
20 x 10 ^3 microsecond = ? u get 20 x 10 ^ 3 cm, impossible
hence answer is B

can you please check and tell me whether my explanation is right for this qyestion
thanks

 

[Capricedcapri]

so copper and diamond and glass are crystalline?????? sorry i didnt get it

no only copper and diamond are crystalline glass is not crystalline em sori i realised i wrote glass as the ans the ans is copper.....

 

[Soldier313]

can you please check and tell me whether my explanation is right for this qyestion
thanks

everythin was similar to the way i understood, except that for the choice B u said that half wave would be displayed....while i thought 5 waveforms will be displayed....

 

[Capricedcapri]

geek101 Capricedcapri
qn 5 on/11, v 1:
3000 revolutions per minute = 50 revolutions per second, which is basically the frequency
so 50 Hz u use this to find periodic time since T = 1/f
u get 20ms as periodic time -----> 0.02s
then i am not sure if this is the appropriate way of doing it but i used each of the choices and tested like this:
A. ) 1s = 1cm
0.02s = ? u get 0.02 cm so basically each wave occupies just 0.02 cm that's a very high freq and waveforms wont be clear
B. ) 10 ms = 1cm
20ms = ? 2cm , that means each wave will occupy 2 cm, so i will have 5 waveforms, pretty clear
C. ) 100 microsecond = 1cm
20 x 10^ 3 microsecond = ? u get 200cm , whoa! that's impossible , i only have 10 cm on the screen
D .) 1 microsecond = 1cm
20 x 10 ^3 microsecond = ? u get 20 x 10 ^ 3 cm, impossible
hence answer is B

ROCKING DUDE!!.....................U'RE GONNA GET THE SHIT OUT OV 2DAY'S PAPER!!....LOL

 

[Capricedcapri]

ANYONE PLZ HELP ME WID MCQ 8 OF OCT NOV 2010 V11

 

[Soldier313]

ROCKING DUDE!!.....................U'RE GONNA GET THE SHIT OUT OV 2DAY'S PAPER!!....LOL

lol tx.....chill girl!
inshaAllah i hope we do get amazing As

 

[1357913579]

everythin was similar to the way i understood, except that for the choice B u said that half wave would be displayed....while i thought 5 waveforms will be displayed....

soory i didnt undersant 5 wave forms like isnt it 1/2 wave lenght